What is the Temperature of a 60W Lamp Filament?

AI Thread Summary
The discussion focuses on calculating the temperature of a 60-watt lamp filament using the Stefan-Boltzmann equation. The user attempts to solve the equation Q = εσAT^4, substituting values for absorptivity, area, and the Stefan-Boltzmann constant. The calculated temperature is approximately 4169.894 K, but there are concerns about significant figures and unit accuracy. Despite these issues, the user notes that the answer aligns with a provided correct value of 3800 K from their question sheet. The conversation emphasizes the importance of precision in calculations and unit consistency in physics problems.
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Homework Statement



Determine the temperature of the filament of a 60watt lamp, if the filament has an area of 10mm^2 and an absorptivity of 0.35. Assume stefan-Boltzmann constant is 5.67*10^-8 W/(m.K^4).

Homework Equations





The Attempt at a Solution



The equation I have attempted with is

Q= εσAT^4

60= 0.35*(5.67*10^-8)*(0.00001m^2)*(T^4)

T^4= 60/(0.35* 5.67*10^-8* 0.00001)

then 4th root of answer = 4169.894

is this correct?
 
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Looks correct with the following comments:

Your answer has too many significant figures.
Your units for the Stefan-Boltzmann constant are wrong.
 
Thats what I have been given on my question sheet, also they just give numerical answers and on the sheet it says the correct answer is 3800K that is why i put it up to check??
 
I compute the same answer as you did.
 

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