What is the tension in the string for circular motion of keys?

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Homework Help Overview

The discussion revolves around a problem involving circular motion, specifically focusing on the tension in a string when swinging keys in a vertical circle. The keys have a combined mass of 0.100 kg and are attached to a 0.25 m long string.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of the minimum speed required for circular motion and the tension in the string at the bottom of the circle. There is a focus on the radius of the circular path and its relationship to the length of the string.

Discussion Status

Participants are exploring different interpretations of the problem, particularly regarding the radius and its implications for calculations. Some have suggested using Newton's second law to analyze the forces acting on the keys, while others question the assumptions made about speed and radius.

Contextual Notes

There is some uncertainty about whether the length of the string should be considered the radius of the circular path. Participants are also discussing the implications of minimum speed at different points in the circular motion.

fa08ti
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Keys with a combined mass of 0.100 kg are attached to a 0.25m long string and swung in a circle in the vertical plane.
a) What is the slowest speed that the keys can swing and still maintain a circular path?
b) What is the tension in the string at the bottom of the circle?


for part a, I used g= v^2/r and rearranged it to v=sqrt(gr)
I got v=2.5 m/s
I'm pretty sure that's right

I think i'd have to use the same equation for the part b?

I'm just stuck on the radius thing for part b
any ideas would be great
 
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fa08ti said:
for part a, I used g= v^2/r and rearranged it to v=sqrt(gr)
I got v=2.5 m/s
I'm pretty sure that's right
What did you use for 'r'?

I think i'd have to use the same equation for the part b?
Use Newton's 2nd law.

I'm just stuck on the radius thing for part b
There's only one radius.
 
I used 0.25 m...that doesn't seem accurate now
 
and isn't the second law F=ma? how would that help since I only know the mass
 
fa08ti said:
I used 0.25 m...that doesn't seem accurate now
Why do you say that?
 
well the question said the length of the string is 0.25m. It didn't say the radius was that length. Would I be correct in assuming that the length of the string is the radius?
 
fa08ti said:
and isn't the second law F=ma? how would that help since I only know the mass
You need to identify the forces acting on the keys when they are at the bottom.

What's unclear to me is what speed you're supposed to use at that point. Are you to assume a constant speed as it goes around the circle? (It would naturally pick up speed as it falls.)
 
fa08ti said:
well the question said the length of the string is 0.25m. It didn't say the radius was that length. Would I be correct in assuming that the length of the string is the radius?
Yes. The keys are at the end of the string, thus the string becomes the radius of the circle. (Someone's hand is the center of that circle, presumably.)
 
Wouldn't I just use the answer from part a?
 
  • #10
fa08ti said:
Wouldn't I just use the answer from part a?
I wouldn't think so. The minimum speed is attained at the top; you'd need to figure out the speed at the bottom.

Even part a is a bit ambiguous: Do they want the minimum speed at any point or the minimum speed at the bottom to reach the top?
 
  • #11
It would be at any point
 
  • #12
fa08ti said:
It would be at any point
Which is what you solved for with the formula you used for part a. (You need to redo your calculation with the correct radius.) The point of minimum speed is at the top of the circle.
 
  • #13
how do i know what the correct radius is?
 
  • #14
fa08ti said:
how do i know what the correct radius is?
The radius is given; it's the length of the string. (I thought I answered that one.)
 

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