What Is the Total Energy Stored in a Magnetic Field Outside a Sphere?

AI Thread Summary
To determine the total energy stored in a magnetic field outside a sphere of radius R, the energy density equation u = B^2/(2μ0) is essential. The magnetic field outside the sphere is given by B = B0(R/r)^2. The total energy can be calculated by integrating the energy density over the volume from r = R to r = ∞, using dV = 4πr^2 dr. The integration leads to the result E = 2πB0^2R^3/μ0, which is consistent with the correct approach to the problem. Proper setup of the calculus is crucial for arriving at the accurate total energy value.
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Homework Statement


Assume that the magnitude of the magnetic field outside a sphere of radius R is B = B0 (R/r)^2. Determine the total energy stored in the magnetic field outside the sphere.

Homework Equations


I think it's necessary to use the energy density equation.
u = B^2/(2*u0)

total energy = u * volume.

The Attempt at a Solution


By just plugging in the given data, I come up with (2*pi*B0^2*R^3)/(u0*3). Assuming that r = R. Or 2*pi*B0^2*R^4/(3r*u0) if I don't assume that. My book's answer is similar except that the 3 in the denom. is not there. So I think I need to use calculus but I don't quite see how to set it up...
 
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jesuslovesu said:

Homework Statement


Assume that the magnitude of the magnetic field outside a sphere of radius R is B = B0 (R/r)^2. Determine the total energy stored in the magnetic field outside the sphere.

Homework Equations


I think it's necessary to use the energy density equation.
u = B^2/(2*u0)

total energy = u * volume.

The Attempt at a Solution


By just plugging in the given data, I come up with (2*pi*B0^2*R^3)/(u0*3). Assuming that r = R. Or 2*pi*B0^2*R^4/(3r*u0) if I don't assume that. My book's answer is similar except that the 3 in the denom. is not there. So I think I need to use calculus but I don't quite see how to set it up...
I don't understand your statement "Assuming that r = R". r is the distance from the centre. R is the radius of the sphere.

You have to integrate the energy density over volume from r=R to r = \infty. All you have to know is that dV = 4\pi r^2 dr

So:

E = \int_R^{\infty} U dV = \int_R^{\infty} U 4\pi r^2 dr

where

U = \frac{B^2}{2\mu_0} and

B = B_0\frac{R^2}{r^2}

You should end up with U as a function of 1/r^2.

The answer I get is:

E = 2\pi B_0^2R^3/\mu_0

AM
 
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