What is the Total Work Done to Reach a Speed of 60 mph?

AI Thread Summary
To calculate the total work done to accelerate a car with a mass of 1604 kg to a speed of 60 mph, the kinetic energy (KE) must be correctly calculated using the formula KE = 0.5 * m * v^2. The initial calculation of KE was incorrect due to the use of improper units, as speed must be converted from mph to m/s for accurate results. After conversion, 60 mph equals approximately 26.82 m/s, leading to a corrected KE value. The total work done is equal to the change in kinetic energy, which is derived from the correct calculations. Understanding unit conversion is essential for solving physics problems accurately.
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if a cars mass is 1604 kg and it is traveling at a speed of 60 mph ...then it's KE is .5 X 1604 X 60 squared = a KE of 2,88,200 J ...now...my question is...using the work energy theorem - what is the TOTAL WORK done to get to a speed of 60 mph ??
 
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What are your thoughts? Assume the car starts from rest. Note that your calculation for the car's KE is incorrect (units!).
 
then wouldn't the total work be 2,887,200 J ? that IS the diff in KE I think !
 
Yes, the change in kinetic energy is the total work done. But your math is off (in the units), you forgot to convert mi/hr to m/s.
 
jay ! thanks so much ! could u help me convert them please !?
 
For a start, 66 mph = 88 ft/s , exactly.
 
can anyone help me understand this - I don't know how to convert 60 mph to ms

the original problem is - if a cars mass is 1604 kg and it is traveling at a speed of 60 mph ...then it's KE is .5 X 1604 X 60 squared = a KE of 2,88,200 J ...now...my question is...using the work energy theorem - what is the TOTAL work done to get to a speed of 60 mph ??
 
1 mile = 1.609 km = 1609 meters, 1 hour = 3600 seconds. so 60*1609 divided by 3600 gives you m/s which equals 26.81667 m/s
 
thanks all- but I'm more confused than ever now ! the original problem was - - if a cars mass is 1604 kg and it is traveling at a speed of 60 mph ...then it's KE is .5 X 1604 X 60 squared = a KE of 2,88,200 J ...now...my question is...using the work energy theorem - what is the TOTAL work done to get to a speed of 60 mph ??

can anyone here solve this ? maybe this is too advanced ? and i am posting it in the wrong topic ? i chose beginners physics cause that's the name of my class here in h school ! err- so frustrating !
 
  • #10
The problem is that the kinetic energy is worked out wrong.

E=\frac{1}{2} m v^2

In order for this to be in Joules the units need to be right. v cannot be in mph. It has to be in m/s, just as mass has to be in kg. All you need to do is convert mph to m/s and use the equation for kinetic energy.
 
  • #11
thank you so much ! finally making sense now ! but how do i convert mph to m/s ? is there a website that can do that for me ? thanks sooooo much
 
  • #12
You should be able to do it yourself. Currently you have miles per hour and you want metres per second. How many metres do you travel in one second if you travel a certain amount of miles in one hour?

If you travel 1 mile in an hour how many metres is that per hour, how many metres is it per second?
 
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  • #13
Groundhog Day. Bueller?
 
  • #14
total work done = net change in KE.
 
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