What Is the True Energy Cost of Achieving a Fusion Energy Gain Factor?

AI Thread Summary
The discussion focuses on the fusion energy gain factor (Q), which measures the ratio of energy produced to energy used for ignition in fusion reactors. Current Q factors include JET at 0.7, ITER projected at 10, and DEMO at 25, but these figures do not account for the energy needed to power toroidal magnets. The conversation highlights the importance of including all energy inputs, particularly for achieving a break-even point, which requires a Q factor over 20 due to various energy demands like current drive and refueling. Participants express interest in understanding the specific energy requirements for toroidal magnets and the potential benefits of superconducting electromagnets. Overall, accurate calculations and transparency in reporting Q values are emphasized as crucial for the future of fusion energy development.
stevebd1
Science Advisor
Insights Author
Messages
747
Reaction score
41
I have a general interest in fusion energy and I'm currently looking at the 'fusion energy gain factor' (Q) of fusion reactors (the energy produced divided by the energy used to induce ignition). I'm aware that the JET recorded a Q factor of 0.7 in 1997, the ITER is anticipated to have a Q factor of 10 and the DEMO a Q factor of 25. The Q factor doesn't include the energy used to power the toroidal magnets and I would be interested to know what power these would require and by how much superconducting electromagnets would reduce energy use (power consumption being negligible in the steady field state for SC electromagnets). I've read that for a fusion power station to break even, the Q factor would have to be over 20 due to the power required for current drive, refuelling, profile control and burn control, I'd be interested to know how the factor of 20 'breaks down' regarding these different aspects of energy use (specifically the powering ot the toroidal magnets).

regards
Steve
 
Last edited:
Engineering news on Phys.org
stevebd1 said:
I have a general interest in fusion energy and I'm currently looking at the 'fusion energy gain factor' (Q) of fusion reactors (the energy produced divided by the energy used to induce ignition). I'm aware that the JET recorded a Q factor of 0.7 in 1997, the ITER is anticipated to have a Q factor of 10 and the DEMO a Q factor of 25. The Q factor doesn't include the energy used to power the toroidal magnets and I would be interested to know what power these would require and by how much superconducting electromagnets would reduce energy use (power consumption being negligible in the steady field state for SC electromagnets). I've read that for a fusion power station to break even, the Q factor would have to be over 20 due to the power required for current drive, refuelling, profile control and burn control, I'd be interested to know how the factor of 20 'breaks down' regarding these different aspects of energy use (specifically the powering ot the toroidal magnets).

regards
Steve
One has to properly define Q for it to be useful. I've learned scientific Q vs engineering Q-values.

Here is a reasonable discussion. Technically the energy input must includes all energy inputs including that used to establish and maintain confinement.

Wikipedia said:
The fusion energy gain factor, usually expressed with the symbol Q, is the ratio of fusion power produced in a nuclear fusion reactor to the power required to maintain the plasma in steady state.
http://en.wikipedia.org/wiki/Fusion_energy_gain_factor

It doesn't address all the details and nuances, but it is one I can readily get my hands on. :rolleyes:
 
Thanks for the reply Astronuc. I sent an email to EURATOM/UKAEA Fusion Association at Culhum Science Centre asking the same question but I'm yet to get a reply.

One thing I did find on the web was an interactive simulator for ITER (you can choose between ITER 85 and 05) where you decide the strength of the magnetic confinement, the power input and amount of fuel used (a dial tells you underneath how much power you are using). You can also configure the cross section of the plasma to obtain optimum output. Dials to the left tell you how much energy you're producing (taking into account the energy used). Apparently, you should get an output of 1000 MW. Though obviously this isn't hard evidence of the energy used by the magnetic confinement, it's still an interesting simulation.

Link- http://fusion.gat.com/diii-d_global/simulation/jstar/
 
Last edited by a moderator:
stevebd1 said:
Thanks for the reply Astronuc. I sent an email to EURATOM/UKAEA Fusion Association at Culhum Science Centre asking the same question but I'm yet to get a reply.

One thing I did find on the web was an interactive simulator for ITER (you can choose between ITER 85 and 05) where you decide the strength of the magnetic confinement, the power input and amount of fuel used (a dial tells you underneath how much power you are using). You can also configure the cross section of the plasma to obtain optimum output. Dials to the left tell you how much energy you're producing (taking into account the energy used). Apparently, you should get an output of 1000 MW. Though obviously this isn't hard evidence of the energy used by the magnetic confinement, it's still an interesting simulation.

Link- http://fusion.gat.com/diii-d_global/simulation/jstar/

Hey, that's fun! I had found something similar a while back, it looks about the same here.

I got 1405 MW of electrical output. I suppose the introductory fusion class helped. :smile:
 
Last edited by a moderator:
stevebd1 said:
I have a general interest in fusion energy and I'm currently looking at the 'fusion energy gain factor' (Q) of fusion reactors (the energy produced divided by the energy used to induce ignition).

Steve,

Q simply refers to the energy quotient as you describe above, and by rights all energy should be taken into consideration. There are always suspicions that the big labs fiddle the numbers and leave out some important information to make the numbers look better. After all they depend on getting more funding next year.

I atttach a pdf file that gives some information about Q from the JET reactor in Culham.

As you may be aware, I belong to a group of amateur fusioneers at www.fusor.net and we have a simple method of calculating Q, where we include all energy in (except the energy required to drive vacuum pumps).

I have set up a permanent Q calculator at

http://www.beejewel.com.au/research/fusion_calculator.htm"

,that anyone with a bubble detector can use, even the big guys if they dare :)

The reason we trust the BTI bubble detector is that all electronic detectors are subject to interference by EMF and we have found that neutron readings are often overstated.

In world of amateur fusion we are still aiming to break the Q 1e-8 barrier http://www.fusor.net/board/view.php?bn=fusor_construction&key=1212188288"

Have fun..

Steven
 

Attachments

Last edited by a moderator:
Hello everyone, I am currently working on a burnup calculation for a fuel assembly with repeated geometric structures using MCNP6. I have defined two materials (Material 1 and Material 2) which are actually the same material but located in different positions. However, after running the calculation with the BURN card, I am encountering an issue where all burnup information(power fraction(Initial input is 1,but output file is 0), burnup, mass, etc.) for Material 2 is zero, while Material 1...

Similar threads

Back
Top