To find the natural number n for which the greatest integer function equals 2012, the equation f(n) = [n/1!] + [n/2!] + ... + [n/10!] must be solved. The function f(n) is non-decreasing, and it has been established that f(1000) is less than 2012 while f(2000) exceeds it. Given that the difference between 2000 and 1000 is less than 2^10, a binary search or bisection method can efficiently determine the value of n in about 10 iterations. This approach allows for precise identification of n that satisfies the equation. The solution process highlights the effectiveness of numerical methods in solving such problems.