What is the value of the loss volt and internal resistance of the battery?

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SUMMARY

The discussion focuses on calculating the loss volt and internal resistance of a battery when a current of 2A causes the terminal voltage to drop from 12V to 9V. The loss volt is determined to be 3V, calculated as the difference between the initial and final voltages. The internal resistance is calculated using the formula R = V/I, yielding a value of 1.5 ohms. The initial attempt to multiply the loss volt by the internal resistance was incorrect, as it resulted in units that do not correspond to voltage.

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looi76
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Homework Statement


When a current of 2A flows the p.d across a battery's terminal falls from 12V to 9V.
(a) What is the value of the loss volt?
(b) What is the internal resistance of the battery?

Homework Equations


Lost Volt = Ir

The Attempt at a Solution


(a) 12V - 9V = 3V

R = \frac{V}{I} = \frac{3}{2} = 1.5

Lost Volt = 3 \times 1.5 = 4.5

Is this correct?

(b) Don't know which equation to use :confused:
 
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your last 4.5 is wrong and no need. It is (lost volt)*(internal rezistance of battery) and meaningless.

Lost volt: 3V
R=1.5 ohm
 
looi76 said:

Homework Statement


When a current of 2A flows the p.d across a battery's terminal falls from 12V to 9V.
(a) What is the value of the loss volt?
(b) What is the internal resistance of the battery?

Homework Equations


Lost Volt = Ir

The Attempt at a Solution


(a) 12V - 9V = 3V

R = \frac{V}{I} = \frac{3}{2} = 1.5

Lost Volt = 3 \times 1.5 = 4.5

Is this correct?

You can always check by using units in the calculation:
3V \times 1.5 \mbox{ohms} = 4.5 \ V\times \mbox{ohms}

Since the units (V x ohms) are not Volts, this can't be right.

(b) Don't know which equation to use :confused:

R = V/I, you already did it without realizing it :smile:
 

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