What is the velocity after parachute opens?

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To determine the velocity of the drag racer after the parachute opens, first calculate the speed at the moment the parachute deploys, using the initial acceleration of +23.0 m/s² over 402 m. Then, apply the negative acceleration of -6.70 m/s² over the distance of 335 m (3.35 x 10² m) to find the final speed. Clarification was needed regarding the distance after the parachute opens, which is confirmed as 335 m. The discussion highlights the importance of correctly interpreting the problem to arrive at the solution. Understanding these steps is crucial for solving similar physics problems.
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hi,

i am having trouble with figuring out this problem.

A drag racer, starting from rest, speeds up for 402 m with an acceleration of +23.0 m/s2. A parachute then opens, slowing the car down with an acceleration of -6.70 m/s2. How fast is the racer moving 3.35 102 m after the parachute opens?

I have no clue where to start or what to do. please help!

thanks,

Z
 
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deuceszbigz said:
hi,

i am having trouble with figuring out this problem.

A drag racer, starting from rest, speeds up for 402 m with an acceleration of +23.0 m/s2. A parachute then opens, slowing the car down with an acceleration of -6.70 m/s2. How fast is the racer moving 3.35 102 m after the parachute opens?

I have no clue where to start or what to do. please help!

thanks,

Z

Find the speed the moment the parachute opens. From that you can answer the question... What exactly is the question though... "How fast is the racer moving 3.35 102 m after the parachute opens?"

is it 3.35m or 102m?
 
i mis-typed. it is supposed to be 3.35*10^2
 

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