What is the velocity of neutrinos, and do their interact with the HIggs field?

ensabah6
Messages
691
Reaction score
0
If Neutrinos have mass, What is the velocity of neutrinos,
can they "slow down" due to gravity, and do their acquire their mass from interactions with the HIggs field?
 
Physics news on Phys.org
For neutrinos of reasonable energy, the velocity will be extremely close to the speed of light; but, it will depend on how much energy they have, just as with any other particle.

It is not currently know exactly how neutrinos acquire mass. There are quite a few models out there. The simplest mechanism is the same Higgs mechanism through which all the other particles acquire mass. However, this requires two things. First, there must be right-handed neutrinos, which no one has ever seen. And, the neutrino coupling to the Higgs field must be ridiculously small (something like 8 orders of magnitude smaller than the electron Higgs coupling). This second requirement, in particular, has led people to look for other ways to make the neutrino mass small more naturally. However, every such method requires adding new physics that there is no experimental evidence for. So, suffice it to say, this is still an open question.
 
Parlyne said:
For neutrinos of reasonable energy, the velocity will be extremely close to the speed of light; but, it will depend on how much energy they have, just as with any other particle.

It is not currently know exactly how neutrinos acquire mass. There are quite a few models out there. The simplest mechanism is the same Higgs mechanism through which all the other particles acquire mass. However, this requires two things. First, there must be right-handed neutrinos, which no one has ever seen. And, the neutrino coupling to the Higgs field must be ridiculously small (something like 8 orders of magnitude smaller than the electron Higgs coupling). This second requirement, in particular, has led people to look for other ways to make the neutrino mass small more naturally. However, every such method requires adding new physics that there is no experimental evidence for. So, suffice it to say, this is still an open question.

So could neutrinos with really low kinetic energy be cold dark matter candidate? Presumably gravity can slow them down.

Is the mass of neutrinos rest mass?
 
ensabah6 said:
So could neutrinos with really low kinetic energy be cold dark matter candidate? Presumably gravity can slow them down.

No, I'm afraid not. They just don't have enough mass to be able to form the halos of galaxies early in the universe's evolution. They would have to have had far less kinetic energy than we know them to have had.

Is the mass of neutrinos rest mass?

Yes. When people talk about the mass of any fundamental particle, what they mean is rest mass (or, equivalently, what you get by calculating \frac{\sqrt{E^2 - p^2c^2}}{c^2}). In the case of neutrinos, though, this is so small that we can't measure it directly. In fact, so far all the neutrino mass measurements we have are actually measurements in the differences between the squares of the masses of different neutrino species. We don't actually know the overall scale of the masses.
 
Thread 'Why is there such a difference between the total cross-section data? (simulation vs. experiment)'
Well, I'm simulating a neutron-proton scattering phase shift. The equation that I solve numerically is the Phase function method and is $$ \frac{d}{dr}[\delta_{i+1}] = \frac{2\mu}{\hbar^2}\frac{V(r)}{k^2}\sin(kr + \delta_i)$$ ##\delta_i## is the phase shift for triplet and singlet state, ##\mu## is the reduced mass for neutron-proton, ##k=\sqrt{2\mu E_{cm}/\hbar^2}## is the wave number and ##V(r)## is the potential of interaction like Yukawa, Wood-Saxon, Square well potential, etc. I first...
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...

Similar threads

Replies
1
Views
2K
Replies
8
Views
2K
Replies
11
Views
2K
Replies
9
Views
2K
Replies
11
Views
3K
Replies
7
Views
3K
Back
Top