What is the voltage at the service with a 20V drop on a 3ph line of 347/600?

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Discussion Overview

The discussion revolves around understanding the implications of a 20V voltage drop on a three-phase line operating at 347/600 volts. Participants explore the resulting voltage at the service and the conceptual framework behind voltage drops in three-phase systems.

Discussion Character

  • Conceptual clarification
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions whether the voltage at the service is 327V or 580V, or if both could be correct given a 20V drop.
  • Another participant asks for clarification on who observed the voltage drop and how it was measured, indicating a need for more context.
  • A participant clarifies that the discussion is not homework-related and expresses an assumption that the operating voltage is 580V due to the three-phase nature of the system.
  • One participant explains the relationship between the specified voltages of 347V and 600V, noting that the three phases are separated by 120° and that the voltage between phases is derived from the single-phase voltage multiplied by √3.
  • The same participant provides calculations indicating that a 20V single-phase drop corresponds to a 34.6V three-phase drop, while a 20V three-phase drop corresponds to an 11.5V single-phase drop.

Areas of Agreement / Disagreement

Participants express differing views on the voltage at the service, with some supporting the idea of 580V and others questioning the measurement context. The discussion remains unresolved regarding the exact voltage at the service.

Contextual Notes

There are limitations in the discussion regarding the assumptions made about the voltage drop measurements and the definitions of the voltages involved. The relationship between single-phase and three-phase voltage drops is also not fully resolved.

rozilla
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Hi guys,

If there was a voltage drop of 20V on a 3ph line of 347/600, is the voltage at the service 327V or 580V, or both? Thanks you for reading.

RozilΩ
 
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Is this a homework problem? What do YOU think the answer is, and why?
 
Who observed a voltage drop of 20V ?
How did they measure it ?
 
Hi guys,

This isn't school related. That isn't the actual voltage - I'm trying to understand the concept of which would be the operating. With the concept, I can apply it accordingly. I assume it is 580 as it is three phase.
 
The specified voltage is 347V / 600V.
The three phases are separated by 120°. 1 / Tan(30°) = √3 = 1.73205
If you multiply 347V by √3 you get 600V.
You cannot change one without changing the other.

When combined with a common neutral you have three single phase supplies of 347V, relative to the neutral. The voltage between the phases is 600V.

A 20V single phase drop is a 34.6V three phase drop.
A 20V three phase drop is an 11.5V single phase drop.
 

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