What is the Width of the Antenna for Optimizing TV Reception on Channel 10?

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SUMMARY

To optimize TV reception on channel 10, which operates at a frequency of 200 MHz, the width of the half wavelength dipole antenna should be calculated as half the wavelength of the signal. The wavelength (λ) can be determined using the formula λ = c/ν, where c is the speed of light (approximately 3 x 108 m/s) and ν is the frequency in Hz. For channel 10, λ equals 1.5 meters, making the optimal antenna width 0.75 meters.

PREREQUISITES
  • Understanding of electromagnetic wave properties
  • Familiarity with the formula λ = c/ν
  • Basic knowledge of dipole antennas
  • Ability to perform unit conversions (MHz to Hz)
NEXT STEPS
  • Research the design principles of dipole antennas
  • Learn about the impact of antenna length on signal reception
  • Explore the effects of frequency on antenna performance
  • Investigate other types of antennas for TV reception
USEFUL FOR

Electronics students, amateur radio enthusiasts, and anyone involved in optimizing TV reception will benefit from this discussion.

Okazaki
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Homework Statement


The half wavelength "dipole" loop roof television antenna is most sensitive to electromagnetic waves with a wavelength twice the width of the antenna. The frequency of the waves for TV channel 10 is 200 MHz. If you want to optimize the TV reception for channel 10, how wide would you construct this antenna?

Homework Equations


f = v/λ = ω/(2π) = n (v/2L)
v = ω/k = λ/T = λf

The Attempt at a Solution


No matter how hard I try, everything keeps cancelling out. I just can't do this problem!

ω = 2πf
T = 1/f
k = vω
v = 2Lω/(2πn)
= Lω/(πn)

But now, there are just too many unknowns. I don't even know where to begin to substitute. :/ I'm just so frustrated right now. Waves are killing me. I have like, three problems left in this homework assignment, and none of them make sense to me (so I can't skip this one and move on.)
 
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What's the wavelength of the 200 MHz signal?
Then it says the antenna width should be half the wavelength of the signal.
What could be simpler?
 
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rude man said:
What's the wavelength of the 200 MHz signal?
Then it says the antenna width should be half the wavelength of the signal.
What could be simpler?

Oh, λν = c.

Literally, the one formula not in my book.
 
Okazaki said:
Oh, λν = c.

Literally, the one formula not in my book.
C'mon, has to be! :smile:
 
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