What Path Does a Charge Take in an AC Solenoid?

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SUMMARY

The path of a charge in an AC solenoid is influenced by the Lorentz Force law, which states that a charged particle experiences a force when moving perpendicular to the magnetic field. In a cylindrical solenoid, the magnetic field is parallel to the axis and reverses direction with alternating current. A positively charged particle moving radially outward will experience a centripetal force, resulting in circular motion within the solenoid. The radius of curvature can be calculated using the formula r=qB/mv, where r is the radius, q is the charge, B is the magnetic field strength, m is the mass, and v is the velocity of the particle.

PREREQUISITES
  • Understanding of the Lorentz Force law
  • Familiarity with cylindrical solenoids and their magnetic fields
  • Basic knowledge of circular motion and centripetal force
  • Ability to manipulate equations involving charge, magnetic field, and velocity
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  • Study the effects of alternating current on magnetic fields in solenoids
  • Learn about the application of the Lorentz Force in particle physics
  • Explore the relationship between frequency of AC and particle motion in magnetic fields
  • Investigate the concept of helical motion in charged particles within magnetic fields
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Physics students, electrical engineers, and researchers interested in electromagnetism and particle dynamics in magnetic fields.

boooster
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Hi,

I was wondering about the path a charge placed in a solenoid that was flown through by alternating current would take. Would it move on a circularly?

Thanks!
 
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erm, well the magnetic field generated by a (cylindrical) solenoid is parallel to the axis of the cylinder the coils are wound around( and to a good approx uniform over the cylinder's cross section). If you reverse the current then the magnetic field will be in the opp direction, i.e. still parallel to axis but in other direction.

Magnetic fields interact with charged particles via the Lorentz Force law: F=q(v x B) (assuming no net electric fields present). Thus there is only a force on the particle if it moves perpendicular to the cylinder's axis (radially in cylindrical polar coords).

If a +ve particle initially moves radially outwards from the centre, and the current is such that the mag field inside the solenoid is to the right, the particle will experience a force that is again radially outward but at 90 degrees to the plane containing v and B. If the current was DC this would lead to the particle moving in a circle in the plane of the solenoid's cross section (I think as long as v isn't to great relative to field strength, otherwise it might leave the solenoid and be out of the mag field, hence it would fly off).

Now assuming the particle is moving along some orbital trajectory, reversing the field would mean the centripetal force also reverses direction so the particle begins moving on a *different orbital path* that touches the first.

I have attached a jpeg of what I think it would look like. To get the actual radius of curvature that the particle moves along you would have to use:

mv^2/r=qvB

=>r=qB/mv

and the portion of the circles orbit completed before "jumping onto another circular orbit" would depend on the AC frequency.

If particle was moving parallel to axis as well as radially, you'd probably end up with a kind of screwdriver motion, helix upon anti-helix, upon helix etc, that's my best guess anyway...
 

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