What Tension Must Ellen Maintain to Steady the Piano Descent?

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To maintain a steady descent of a 500 kg piano being lowered by a crane, the tension in Ellen's rope must balance the horizontal forces exerted by Bob's rope. Bob's rope has a tension of 500 N, pulling at 15 degrees below horizontal, resulting in horizontal and vertical components of -482 N and -129 N, respectively. Since the piano descends at a steady speed, the net force must be zero, meaning Ellen's horizontal force must counteract Bob's. The calculations show that Ellen's tension must be 532 N to achieve this balance. The vertical forces are not needed for this specific calculation as the crane's vertical pull is already accounted for.
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a 500 kg piano is being lowered into position by a crane while 2 people steady it with ropes pulling to the sides. bob's rope pulls to the left, 15 degrees below horizontal, with 500 N of tension. ellen's rope pulls toward the right, 25 degrees below horizontal. what tension must ellen maintain in her rope to keep the piano descending at a steady speed?

ok so what i understood from this, is that bobs rope is in the 3rd quad and ellens is in the 4th. and i guess there is a main cable from the crane going straight up. and then since is says it is descending at a steady speed that means that there is no net force or acceleration. so i figured i should get the components of bob's rope, Bx=-482 By=-129.
and the i thought that
Fnetx = Bx+Ex =0
-482 + Ecos25 =0
Ecos25=482
E=532
Fnety = By+Ey=o
-129+Esin25=0
E=306
and then i found the magnitude of the two components of E and 614 N. but that is incorrect. so i don't know what to do anymore!
 
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It's the total force on the piano that must be zero, including the force of the crane (not just Bob and Ellen's force). But you know (or can assume) that the crane is just pulling vertically. So the only horizontal forces are exerted by Bob & Ellen, so the horizontal components of their forces must add to zero. And that's all you need to find Ellen's force. (You've already done the calculation.)
 
so is ellen's force 532 N? b/c i am not understand why you do not need bob and ellens vertical component force?
 
klm said:
so is ellen's force 532 N? b/c i am not understand why you do not need bob and ellens vertical component force?
That's correct. Since they are just steadying the crane, their total horizontal force must be zero. That's all you need to solve the problem. Their vertical force isn't zero, because the crane add its force to the piano. (The crane pulls vertically.)
 
thank you doc al
 
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