What Value of d/a Causes Diffraction to Eliminate the Third Bright Side Fringe?

AI Thread Summary
In a double-slit system, the discussion centers on determining the values of d (slit separation) and a (slit width) that result in the elimination of the third bright side fringe due to diffraction effects. The relevant equations include the intensity formula I(θ) and the conditions for maxima and minima in both interference and diffraction patterns. The problem involves setting d sinθ equal to 3λ for the third maximum and a sinθ equal to (3 + 1/2)λ for the first minimum. A participant expresses confusion about connecting the equations and calculating the correct ratio of d/a, which is initially found to be incorrect. The key point is recognizing that the angle θ must satisfy both the interference and diffraction conditions simultaneously to eliminate the fringe.
Zhalfirin88
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Homework Statement


(a) In a double-slit system, what value of d/a causes diffraction to eliminate the third bright side fringe?

Homework Equations


I(\theta) = I_mcos^2(\beta)(\frac{sin(\alpha)}{\alpha})^2

\beta =\frac{\pi d}{\lambda} sin \theta

\alpha = \frac{\pi a}{\lambda} sin \theta

d sin\theta = 3 \lambda

a sin\theta = (3+\frac{1}{2}) \lambda

The Attempt at a Solution


I solved for a and d in equations 4 and 5 above and got a ratio of 0.857, which isn't right. I'm not sure really how to go about this, I have a feeling that I need to use equations 2 and 3 but I'm not making the connections.
 
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Is everyone as lost as I am with this problem?
 
Zhalfirin88 said:
d sin\theta = 3 \lambda
Yes, the angle θ corresponds to the 3rd maximum (not counting central max) in the 2-slit interference term cos2β

a sin\theta = (3+\frac{1}{2}) \lambda
Actually, the idea here is that θ also corresponds to the first minimum of the diffraction term [(sinα)/α]2
 
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