What Values of (x, y) Make f(x, y) = 1/(x - y^2) Undefined? • Physics Forums

M.Qayyum · 2009-08-23T07:28:17+00:00

Here is my question, that what is the domain of f, while f(x,y)=1/(x-y2)

Thread 'Prove that the integral is equal to ##\pi^2/8##'

Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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What Values of (x, y) Make f(x, y) = 1/(x - y^2) Undefined?

Thread 'Prove that the integral is equal to ##\pi^2/8##'

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