What Was the Average Velocity of the Hiker During the Trip?

AI Thread Summary
The discussion centers on calculating the average velocity of a hiker who walks 6.7 miles east and then 1.1 miles west. It emphasizes that average velocity is a vector quantity and should account for direction, meaning the return trip affects the total distance. The correct approach involves calculating the net displacement and total time, rather than averaging the speeds of each segment. The participants clarify the importance of using parentheses in calculations to ensure accuracy. Ultimately, the average velocity is derived from the net distance divided by the total time.
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Homework Statement



a hiker walks 6.7 miles to the east in 5.1 hours. then turns around and walks 1.1 miles to the west in 1 hour. what was her average velocity during the trip?
A 1.2mph
B 1.3mph
C .92mph
D 3.9mph

Homework Equations


not sure how to write what i used


The Attempt at a Solution


6.7/5.1=1.3
1.1/1=1.1
1.3+1.1=2.4/2=1.2
 
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It seems you're not done yet! :smile:

Let's start with the word "velocity".
Do you know what it means?
That is, is it a scalar or a vector?

Second, the term "average velocity".
What you should know is that you shouldn't average the speeds of the first part and the second part.
Instead you should calculate the total distance and divide that by the total time.
 
velocity is a vector because it has a magnitude and a direction.
so i should do something like 6.7+1.1/5.1+1=7.8/6.1=1.27
 
You just got the "average speed".
To get the "average velocity" you need to take into account that the second part of the trip is back.

(And please add parentheses when they are required. :wink:)
 
okay so how do i do that??
 
Going back is "minus" vector wise.
 
so should i do 6.7-1.1/5.1+1
 
Shall we make that: (6.7-1.1)/(5.1+1)?
The parentheses are really required.
Otherwise you're quite right.
 
okay. i got why the () are required. haha thanks i think I am almost done
 
  • #10
Yeah, I think so too...
 
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