What Water Levels Produce Resonance Frequencies with a Tuning Fork?

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The discussion revolves around determining the water levels at which the first two resonance frequencies can be heard when a tuning fork of 300 Hz is placed on a metal cylinder. The flow rate of water is noted as 10^-6 m^3/s, but it is considered irrelevant for calculating resonance frequencies, which depend on the open-closed system's natural frequencies. The formula for these frequencies is f_n = nv/4L, where n represents odd integers. The first resonance frequency is identified as 300 Hz, leading to a calculated water level of 0.286 m. The conversation also touches on the concept of beat frequency, questioning whether it should be expressed as positive or negative, ultimately concluding that it is always positive due to the absolute value in the formula.
dekoi
There's a metal cylinder from which water is flowing out at a rate of 10^-6 m^3/s. A tuning fork of 300 Hz is placed on top of the cylinder. At what water levels will the first two resonance frequencies be heard?

It doesn't seem like a difficult problem, and it really isn't. I just can't seem to see it.

I don't think the flow rate has any signifiance in calculation; it's only useful to know that the water level is decreasing.

It's an open-closed system, so the natural frequencies are f_n = \frac{nv}{4L} where n = 1, 3, 5, 7...

So in the first case, i think the first frequency heard would be 300 Hz. Hence, one can solve for L_1 to attain 0.286m. But how about for the next? Will it just be 3 times L_1 ? Or how do you solve for it otherwise?Thanks
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Question 2: Is it logical to ask whether the beat frequency is e.g. +4 or -4? Afterall, f_{beat} = |f_2 - f_1| so because of the absolute value,it is always +4.
 
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