kudoushinichi88 said:De Broglie's wavelength is given by the equation
[tex] \lambda = \frac{h}{p} [/tex]
where h is Planck's constant and p is the momentum of the particle. What happens to wave-particle duality if h = 0 should be fairly clear now.
malty said:uhhhhh ...It isn't to me:uhh:
Planck's constant, denoted as "h", is a fundamental constant in quantum mechanics that relates the energy of a photon to its frequency. It is important in wave-particle dualism because it explains the behavior of particles that exhibit both wave-like and particle-like characteristics.
If Planck's constant were to equal 0, it would mean that the energy of a photon is not related to its frequency. This would fundamentally change the concept of wave-particle dualism as it would no longer be able to explain the behavior of particles in the quantum world.
No, wave-particle duality would not exist if Planck's constant were to become 0. This is because wave-particle duality is a result of Planck's constant and is based on the idea that particles can exhibit both wave-like and particle-like properties.
No, Planck's constant is a unique and fundamental constant that is specific to quantum mechanics. It cannot be replaced by any other constant in explaining the wave-particle duality of particles.
Planck's constant plays a crucial role in our understanding of the nature of particles. It helps explain the wave-like and particle-like behavior of particles and sheds light on the mysterious quantum world. Without Planck's constant, our understanding of the fundamental nature of particles would be incomplete.