Whats a non-trivial linear combination of these functions?

warfreak131
Messages
186
Reaction score
0
I have to find a non-trivial, linear combination of the following functions that vanishes identically.

In other words

C1f + C2g + C3h = 0

Where C1, C2, and C3 are all constant, and cannot all = 0.

f(x)=17
g(x)=2Sin2(x)
h(x)=3Cos2(x)

I figure C1 = 0, because there's really no constant relation between the trig functions and 17.

That means that C22Sin2(x)=-C33Cos2(x)

I need help finding C2 and C3. I've already tried substituting with trig identities, but I am getting nothing as of now.
 
Last edited:
Physics news on Phys.org
hi warfreak131! :smile:

c'mon … think! … what's the most famous equation involving cos2 and sin2 ? :wink:
 
tiny-tim said:
hi warfreak131! :smile:

c'mon … think! … what's the most famous equation involving cos2 and sin2 ? :wink:

I know that sin2x + cos2x = 1, and I've tried that, but I am still not getting it

C22Sin2(x)=-C33Cos2(x)

C22(1-cos2(x))=-C33Cos2(x)

C2(2-2cos2(x))=-C33cos2(x)

but this doesn't simplify into a constant solution, as far as i worked it out
 
warfreak131 said:
I know that sin2x + cos2x = 1 …

ok, so what = 17? :smile:

get some sleep! :zzz:​
 
tiny-tim said:
ok, so what = 17? :smile:

get some sleep! :zzz:​
17sin2x+17cos2x?

so C1 = 17Sin2x + 17Cos2x

then just apply another coefficient to 2Sin2x, and 3Cos2x to make the new coefficient equal 17?
 
Last edited:
yup! :smile:

g'night! :zzz:​
 
awesome thanks
 
Back
Top