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What's the antiderivative of

  1. Aug 19, 2008 #1

    how do i figure this out
  2. jcsd
  3. Aug 19, 2008 #2
    is it 1/2 (2x+1)
  4. Aug 19, 2008 #3
    Solve it by u-substitution where u=2x+1
  5. Aug 19, 2008 #4


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    Staff Emeritus
    Science Advisor

    Is that [tex]\frac{2}{2x+1}[/tex]?

    Then along the lines of Feldoh's comment, what is the antiderivative or integral of 1/u

    or [tex]\int\frac{du}{u}[/tex]
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