- #1
brunettegurl
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whats the max force??
A 275.0 g ball is dropped from a height of 2.60 m, bounces on a hard floor, and rebounds to a height of 1.71 m. The impulse received from the floor is shown below. What maximum force does the floor exert on the ball if it is exerted for 8.00 ms?
[tex]\Delta[/tex]p = m1(v2-v1) and [tex]\Delta[/tex]p = 0.5bh
since there's no given velocity i decided to take the differcence between the 2 heights and divide it by the time to get a speed i used the first equation from which i got a change in momentum and then tried to figure out the height since the base = time (8ms) is this reasoning correct??
Homework Statement
A 275.0 g ball is dropped from a height of 2.60 m, bounces on a hard floor, and rebounds to a height of 1.71 m. The impulse received from the floor is shown below. What maximum force does the floor exert on the ball if it is exerted for 8.00 ms?
Homework Equations
[tex]\Delta[/tex]p = m1(v2-v1) and [tex]\Delta[/tex]p = 0.5bh
The Attempt at a Solution
since there's no given velocity i decided to take the differcence between the 2 heights and divide it by the time to get a speed i used the first equation from which i got a change in momentum and then tried to figure out the height since the base = time (8ms) is this reasoning correct??