What's the simple formula for winch/ramp/angle?

  • Thread starter Thread starter prefetch
  • Start date Start date
  • Tags Tags
    Formula
AI Thread Summary
To determine the winch size needed for a 40,000 lb vehicle on a 30-degree ramp, the formula involves calculating the force required using the sine and cosine of the ramp angle, resulting in a need for approximately 37,000 lbs of pulling power. It's important to consider the drag coefficient, which can significantly affect the required winch capacity. Best practices suggest that winch ratings should be at least double the weight of the vehicle for recovery scenarios, especially if the vehicle is stuck in challenging conditions. For a 40,000 lb vehicle, a winch rated for at least 80,000 lbs is recommended. Utilizing snatch blocks can also enhance the pulling capability of the winch.
prefetch
Messages
23
Reaction score
0
i'm not a physics guy, or a mechanical engineer, but i think this should be a really simple formula - I'm assuming some of you folks will know this off the top of your head:

okay, so I'm trying to figure out how big of a winch to buy for a very large tow truck i am building. winches are rated based on how much they can pull. eg. a 20,000 lb winch can pull 20,000 lbs at a 0 degree incline (flat surface.)

so if i have a vehicle that weighs 40,000 lbs, and a ramp angle of 30 degrees, and a drag coefficient of .5 (if I'm towing a disabled tracked vehicle, I'm guessing a drag coefficient as high as .5 isn't unreasonable) then how big of a winch would i need to pull this up the ramp?

i'm looking for a formula, so i can change the values of my variables: weight of vehicle, drag coefficient of vehicle, winch size, angle of ramp.

is this a basic formula that you folks know?
 
Engineering news on Phys.org
You would need a winch that can pull more than:

(40,000 lbs.) * sine(30 degrees) + (0.5) * (40,000 lbs.) * cosine (30 degrees) = ~ 37,000 lbs.

You should be careful about assuming your drag coefficient. Perhaps you could measure the force require to pull a vehicle of some known weight up a hill of some known slope?
 
Skrambles said:
You would need a winch that can pull more than:

(40,000 lbs.) * sine(30 degrees) + (0.5) * (40,000 lbs.) * cosine (30 degrees) = ~ 37,000 lbs.

You should be careful about assuming your drag coefficient. Perhaps you could measure the force require to pull a vehicle of some known weight up a hill of some known slope?


cool. yeah, that's a good idea on the drag coefficient, i guess that makes a big difference. i think i have some ideas on that.

anyway, thanks a bunch! good on you.
 
You also have to consider what the "disabled" vehicle might be stuck in or behind. For 4x4's it's best practice to spec a recovery winch at about double the weight of the veihicle, in case it's stuck in mud or large rocks. This helps to keep the duty cycle and strain on the winch down, in addition to giving you an extra safety factor for rare circumstances. So for a 4500lb SUV, you want your winch to be rated at about 9000lbs; for a 40,000lb tank you'll want the winch to be rated for at LEAST 40,000lbs, and I would aim closer to 80K.

Keep in mind though you can use snatch blocks (pulleys) to double or quadruple the pulling capability of whatever winch you decide on.
 
Posted June 2024 - 15 years after starting this class. I have learned a whole lot. To get to the short course on making your stock car, late model, hobby stock E-mod handle, look at the index below. Read all posts on Roll Center, Jacking effect and Why does car drive straight to the wall when I gas it? Also read You really have two race cars. This will cover 90% of problems you have. Simply put, the car pushes going in and is loose coming out. You do not have enuff downforce on the right...
I'm trying to decide what size and type of galvanized steel I need for 2 cantilever extensions. The cantilever is 5 ft. The space between the two cantilever arms is a 17 ft Gap the center 7 ft of the 17 ft Gap we'll need to Bear approximately 17,000 lb spread evenly from the front of the cantilever to the back of the cantilever over 5 ft. I will put support beams across these cantilever arms to support the load evenly
Thread 'Physics of Stretch: What pressure does a band apply on a cylinder?'
Scenario 1 (figure 1) A continuous loop of elastic material is stretched around two metal bars. The top bar is attached to a load cell that reads force. The lower bar can be moved downwards to stretch the elastic material. The lower bar is moved downwards until the two bars are 1190mm apart, stretching the elastic material. The bars are 5mm thick, so the total internal loop length is 1200mm (1190mm + 5mm + 5mm). At this level of stretch, the load cell reads 45N tensile force. Key numbers...

Similar threads

Replies
9
Views
1K
Replies
1
Views
3K
Replies
17
Views
11K
Replies
28
Views
2K
Replies
7
Views
5K
Replies
14
Views
31K
Replies
9
Views
1K
Back
Top