# What's the solution of Cubic and biquadratic polynomial?

1. Feb 25, 2005

### TheDestroyer

It's very easy to solve the equation for x:

ax^2 + bx + c = 0

The law for the answer will be (-b+-sqrt(delta))/2a

OK, what if i want to solve:

ax^3 + bx^2 + cx + d = 0
ax^4 + bx^3 + cx^2 + dx + e = 0

a,b,c,d,e constants, How i'm gonna solve this for x? isn't there a general law?

2. Feb 25, 2005

### HallsofIvy

Staff Emeritus
3. Feb 25, 2005

### dextercioby

Terminology:A biquadratic (algebraic) equation is a particular case of a quartic...E.g.
$$ax^{4}+bx^{2}+c=0$$

is the general form of a biquadratic equation.Do you see why it bears that name ?

Daniel.

4. Feb 25, 2005

### TheDestroyer

Thanks, Seems the best way is creating a damn program for solving this!!!

5. Feb 25, 2005

### dextercioby

Yes,that's the the modern method lazy people use these days...:yuck:

This is far too simple maths to use a computer.

Daniel.