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What's the solution of Cubic and biquadratic polynomial?

  1. Feb 25, 2005 #1
    It's very easy to solve the equation for x:

    ax^2 + bx + c = 0

    The law for the answer will be (-b+-sqrt(delta))/2a

    OK, what if i want to solve:

    ax^3 + bx^2 + cx + d = 0
    ax^4 + bx^3 + cx^2 + dx + e = 0

    a,b,c,d,e constants, How i'm gonna solve this for x? isn't there a general law?
     
  2. jcsd
  3. Feb 25, 2005 #2

    HallsofIvy

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  4. Feb 25, 2005 #3

    dextercioby

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    Terminology:A biquadratic (algebraic) equation is a particular case of a quartic...E.g.
    [tex] ax^{4}+bx^{2}+c=0 [/tex]

    is the general form of a biquadratic equation.Do you see why it bears that name ?

    Daniel.
     
  5. Feb 25, 2005 #4
    Thanks, Seems the best way is creating a damn program for solving this!!!
     
  6. Feb 25, 2005 #5

    dextercioby

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    Yes,that's the the modern method lazy people use these days...:yuck:

    This is far too simple maths to use a computer.

    Daniel.
     
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