Another classic case of "I understand it in reality, but on paper it just makes no sense and I'm confused". There is an object sliding north on a surface where the normal is 10N. The co-efficient for kinetic friction for the surface is 0.5. Simple math will tell me that the force of friction acting in the opposite direction (south) will be 0.5*10N = 5N. There's also the co-efficient for static friction for when the object isn't moving. Let's say it has the value of 0.6. So I need 6N to overcome static friction and make the object even budge. Everything makes perfect sense so far. But what happens when a force applied isn't strong enough? Would there be a net force in some direction even though the object isn't moving? What happens in the moments when the object stops on its own (read below)? t0 - Object has force 10N north. It slides across the surface. t1 - The object is now moving very slowly due to friction, it's just about to stop. t2 - The force North acting on the object is maybe 4N now. That isn't enough to continue, so the object stops. But what happens to the net force? Is it reduced to 0? If so, what makes it reduce to 0? If I apply a weaker force than the static force the object doesn't move. What is resisting my force. For the cases where I push with a size not large enough, does friction resist with an equal force in the opposite direction?