Where do antireflective coatings reflect light?

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Antireflective coatings on conducting substrates, like a Salisbury screen, cause destructive interference in specular reflection, redirecting reflected light. When light is not transmitted, energy conservation requires it to be reflected in a different direction. The angle of this reflection remains consistent with the angle that would occur without the coating. Refraction affects all light passing through the coating, allowing the main beam to proceed while minimizing reflection. Understanding these principles is essential for calculating the new angle of reflection accurately.
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Lets consider an index matching antireflective coating on a conducting substrate (i.e. salisbury screen). The waves reflected destructively interfere in the direction of specular reflection. However, the energy has to be conserved, and since it is not transmitted, it most me reflected in a different direction. How do i figure out the new angle of reflection?
 
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Hi,

In articles they use the term absorbed when there is no reflection. Is there a basis for your
Christofer Br said:
the energy has to be conserved, and since it is not transmitted, it must me reflected in a different direction
 
Christofer Br said:
How do i figure out the new angle of reflection?
The angle for the inevitable tiny bit of reflected light will be the same as if the coating were not there. The light that would have been reflected will go through with the main beam because the refraction acts on everything that goes through.
 
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