Where Do Knights Collide in a Physics Problem?

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Two knights, Sir George and Sir Alfred, start 78 meters apart and accelerate toward each other with different rates. Sir George has an acceleration of 0.257 m/s², while Sir Alfred accelerates at 0.389 m/s². The problem was initially challenging, but using the equation x = V(0)t + (1/2)at² helped determine the time taken for each knight to reach a collision point. With the hint about summing their accelerations, it was concluded that they collide after Sir George travels 31.03 meters. This solution effectively illustrates the application of kinematic equations in a physics context.
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[SOLVED] Acceleration/Velocity Problem

Homework Statement



In an historical movie, two knights on horseback start from rest 78.0 m apart and ride directly toward each other to do battle. Sir George's acceleration has a magnitude of 0.257 m/s2, while Sir Alfred's has a magnitude of 0.389 m/s2. Relative to Sir George's starting point, where do the knights collide?


Homework Equations



x= V(0)t+ (1/2)at^2

Average Acceleration

Average Velocity

The Attempt at a Solution




Ok I'm first of having trouble finding out where to START in this problem. I decided the best move would to use x= V(0) + (1/2)at^2 to find out how long it would take the two horseback riders to cross all 78 m.

I got t= 24.64 seconds for George
and t= 20.03 seconds for Alfred

What I'm having trouble doing now is setting up an equation that would allow me to figureout when the two riders crashed into each other. Any thoughts?
 
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Hint: the relative accn between the two is the sum of the two accns. Keep George fixed.
 
ahhh good point. thanks to that hint i solved the problem- the answer was it took George 31.03 meters before the collision.

thanks a bunch
 
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