Where Does the Energy Go When a Ball Becomes Embedded?

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Discussion Overview

The discussion revolves around the energy transformations and calculations involved when a ball bearing is dropped from a height and becomes embedded upon impact. It includes theoretical aspects of energy changes, internal energy calculations, and temperature increases related to specific heat capacity.

Discussion Character

  • Exploratory
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant inquires about the energy changes that occur when a ball bearing is dropped and becomes embedded, seeking to understand the transition from gravitational potential energy (GPE) to kinetic energy.
  • Another participant emphasizes the significance of the term "becomes embedded," suggesting that it implies energy conservation in different forms rather than bouncing, prompting questions about where the energy goes.
  • There is a request for clarification on the calculations of internal energy increase and temperature change, indicating uncertainty about how to approach these problems.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the energy transformations and calculations, with no consensus reached on the specifics of how energy is conserved or transformed when the ball bearing becomes embedded.

Contextual Notes

Participants have not explicitly stated all assumptions made in their calculations or reasoning, and there are unresolved steps in the mathematical processes discussed.

Who May Find This Useful

Students studying energy transformations in physics, particularly those working on problems related to mechanics and thermodynamics.

barnacksam
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Ive got this question but i don't know how to answer it.

A steam boiler produces steam at a rate of 0.5 kg.s-1. If the specific latent heat of vaporisation of water is 2.3 MJ kg-1:

(a) What power is consumed to achieve this rate?

cheers
 
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You have the mass flow rate and the specific energy required, so all you need to do is multiply the mass flow rate by the specific energy to get a result of MJ/s, also known as a megawatt (MW).

\frac{kg}{s} * \frac{MJ}{kg} = \frac{MJ}{s} = MW
 
thanks a lot
 
Just working through a past paper atm, just need a hand with this one as well ha

A ball bearing, of mass 200 g, is dropped from the top of a 200 m building; it falls to the ground and becomes embedded.

(a) Describe the energy changes which take place.
(5 marks)

(b) What is the increase in internal energy of the ground and the ball bearing at the point of impact?
(5 marks)

(c) Calculate the temperature increase of the ball bearing if it absorbs 70% of this internal energy.
(5 marks)

State all assumptions made.

Take the specific heat capacity of the metal to be 460 J kg-1 K-1.
 
Why don't you show your own work at an attempted solution? Pay attention to the forms of energy are being presented in the system...
 
Ive gone from GPE to kinetic, then i don't understand what happens when it becomes embedded.
then the b) and c) i just don't have a clue
 
"Becomes embedded" is important because it means the ball doesn't bounce- hence all of that energy is conserved in other areas. If the energy isn't used to bounce the ball, where does it go?
 

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