Where Does the Less Than Symbol Disappear in the Triangle Inequality Proof?

Punkyc7
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Im curios as to why the inquality is
||x+y||\leq||X||+||y||

but the end of the proof is

=(||x||+||Y||)^2

where does the less than symbol disappear too
 
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|x+y|\leq |x|+|y|\Leftrightarrow(|x+y|)^2\leq (|x|+|y|)^2\Leftrightarrow(x+y)^2\leq (|x|+|y|)^2\Leftrightarrow x^2+2xy+y^2\leq|x|^2+2|x||y|+|y|^2\Leftrightarrow x^2+2xy+y^2\leq x^2+2|x||y|+y^2\Leftrightarrow 2xy\leq2|x||y|
xy\leq|x||y|

That is obvious since

x\leq|x| and y\leq|y|
 
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