Slereah
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I am currently trying to find how to derive the decomposition for two particles via the tensor notation, for instance for the product of two particles of spin 1/2 :
\frac{1}{2} \otimes \frac{1}{2} = 1 \oplus 0
Giving the components of spin 1 and 0. So to do it, I write down the product of two spinors and write it as its symmetric and antisymmetric part :
\psi_a \chi_b = \frac{1}{2} (\psi_{[a} {\chi_{b}}_] + \psi_{\{a} {\chi_{b}}_\})
The antisymmetric part is the scalar part, being simply
\psi_{[a} {\chi_{b}}_] = \left( \!\!\begin{array}{cc}<br /> 0&-1\\<br /> 1&0<br /> \end{array}\! \right) (\psi^+ \chi^- - \psi^- \chi^+)
And the symmetric part is something of the form
\psi_{\{a} {\chi_{b}}_\} = \left( \!\!\begin{array}{cc}<br /> 2\psi_+ \chi_+&\psi_+ \chi_- + \psi_- \chi_+\\<br /> \psi_+ \chi_- + \psi_- \chi_+&2\psi_- \chi_-<br /> \end{array}\! \right)
Which looks like it contains all the right components, but then I try to compare it to the actual vector quantity :
V^{ab} = \varepsilon^{ca} V_c^b = \varepsilon^{ca} (\sigma^\mu)_c^b V_\mu = \left( \!\!\begin{array}{cc}<br /> - V_x - i V_y &V_z\\<br /> V_z&V_x - i V_y<br /> \end{array}\! \right)
There may be a sign wrong in here somewhere because of the spinor metric (\varepsilon[\tex], the levi-civita tensor), but even up to a sign, the symmetric part does not really lend itself to being put in vector form, and it would seem to mix the states (+,+) with (-,-) as well. I tried using directly the product of a contravariant and covariant spinor, but it did not help. So where does the problem stem from?
\frac{1}{2} \otimes \frac{1}{2} = 1 \oplus 0
Giving the components of spin 1 and 0. So to do it, I write down the product of two spinors and write it as its symmetric and antisymmetric part :
\psi_a \chi_b = \frac{1}{2} (\psi_{[a} {\chi_{b}}_] + \psi_{\{a} {\chi_{b}}_\})
The antisymmetric part is the scalar part, being simply
\psi_{[a} {\chi_{b}}_] = \left( \!\!\begin{array}{cc}<br /> 0&-1\\<br /> 1&0<br /> \end{array}\! \right) (\psi^+ \chi^- - \psi^- \chi^+)
And the symmetric part is something of the form
\psi_{\{a} {\chi_{b}}_\} = \left( \!\!\begin{array}{cc}<br /> 2\psi_+ \chi_+&\psi_+ \chi_- + \psi_- \chi_+\\<br /> \psi_+ \chi_- + \psi_- \chi_+&2\psi_- \chi_-<br /> \end{array}\! \right)
Which looks like it contains all the right components, but then I try to compare it to the actual vector quantity :
V^{ab} = \varepsilon^{ca} V_c^b = \varepsilon^{ca} (\sigma^\mu)_c^b V_\mu = \left( \!\!\begin{array}{cc}<br /> - V_x - i V_y &V_z\\<br /> V_z&V_x - i V_y<br /> \end{array}\! \right)
There may be a sign wrong in here somewhere because of the spinor metric (\varepsilon[\tex], the levi-civita tensor), but even up to a sign, the symmetric part does not really lend itself to being put in vector form, and it would seem to mix the states (+,+) with (-,-) as well. I tried using directly the product of a contravariant and covariant spinor, but it did not help. So where does the problem stem from?