Where Does the Vector Come to Rest Given u and a?

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To find the position vector when the object comes to rest, the initial velocity is given as u = -14i - 7j and the acceleration as a = 6i + 3j. The user is unsure how to approach the problem, particularly in determining when the velocity equals zero and how to differentiate the equations. Forum members suggest considering the relationships between position, velocity, and acceleration, and inquire whether an initial position vector was provided. They also recommend recalling kinematic formulas that could assist in solving the problem. Understanding these concepts is crucial for determining the resting position of the vector.
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Homework Statement



find the position (r) when the vector comes to rest.

Homework Equations



initially velocity = 'u', acceleration = a
u= -14i-7j
a= 6i+3j

The Attempt at a Solution



hey guys I am new at this so i didnt know how to post it but some help would be great :)
i tried solving it for when v=0 but i didnt know how, neither could i differentiate it :/
 
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thunderflap said:

Homework Statement



find the position (r) when the vector comes to rest.

Homework Equations



initially velocity = 'u', acceleration = a
u= -14i-7j
a= 6i+3j

The Attempt at a Solution



hey guys I am new at this so i didnt know how to post it but some help would be great :)
i tried solving it for when v=0 but i didnt know how, neither could i differentiate it :/

Hi thunderflap, Welcome to Physics Forums.

Were you given an initial position vector too?

What are the (calculus) relationships between position, velocity, and acceleration? If this had been a problem not using vectors and you were given separate x and y components for acceleration and initial velocity, what would your approach be? What kinematic formulas might you employ?
 
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