# Where is f continuous?

1. Aug 9, 2008

### Calcotron

Well, my first question was answered so I figured I would post the second problem I had problems with. It is:

$$f(x) = lim _{n->\infty}\frac{x^{2n} - 1}{x^{2n} + 1}$$

Where is f continuous? My first thought is that it is continuous everywhere since I can't find an x value that would make the bottom part of the fraction 0. Isn't that function 1 at for $$\infty < x \leq-1$$ or $$1 \leq x < \infty$$ and -1 otherwise?

Last edited: Aug 9, 2008
2. Aug 10, 2008

### Calcotron

Lol, let's just pretend this question never happened ok?

3. Aug 10, 2008

### cristo

Staff Emeritus
I take it that means you've solved the question then?