Which Anion Precipitates First in a Pb(NO3)2 Solution?

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In a solution containing 1.5×10−2 M CrO4^2- and SO4^2-, the addition of 0.55 M Pb(NO3)2 will lead to precipitation based on the solubility products of lead compounds. The first anion to precipitate will be determined by comparing the solubility product constants for lead chromate and lead sulfate. As Pb^2+ is added, the concentration must be calculated at which each anion begins to precipitate, considering the dilution effect from the added volume. The relevant solubility product values and initial concentrations of the anions are crucial for determining the order of precipitation. Understanding these concepts will clarify which anion precipitates first and the Pb^2+ concentration at that point.
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Homework Statement




A solution is 1.5×10−2 M in both CrO4^2-and SO4^2-. To this solution, 0.55 M Pb (NO3)2(aq) is slowly added.

Which anion will precipitate first from solution?

a) CrO4^{2-}
b) SO4^{2-}

What is Pb^{2+} concentration at the point at which the second anion begins to precipitate?

Homework Equations





The Attempt at a Solution



k the thing that is confusing me is that the concentration of 0.55 M Pb (NO3)2(aq) was stated. Why is this relevant? because of that i do not know what to do
 
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Things will begin to ppt when the solubility product is reached. You know the value for the solubility product of both lead sulfate and chromate, you know the initial concentrations of the anions, you need to calculate the concentration of lead at each point in the titration. Don't forget to adjust the concentrations of the anions as you add volume from the lead nitrate solution.
 
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