Which Brick Lands with the Highest Speed and Other Physics Enigmas?

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Three bricks thrown from a roof with the same initial speed but different angles will all reach the ground with the same speed, as energy conservation dictates. In a car crash scenario, an inelastic collision where cars stick together is more harmful due to energy loss, while the rebound collision involves greater acceleration changes that can also be harmful. Total mechanical energy can indeed be negative, depending on the reference point chosen for potential energy (PE), which can be negative if the reference point is above the object. Kinetic energy (KE) is always positive, but if the magnitude of negative PE exceeds KE, the total mechanical energy becomes negative. Understanding these principles helps clarify the dynamics of collisions and energy conservation in physics.
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1) Three bricks are thrown from the roof of a building with the same speed but with different launch angles: one above the horizontal, one below the horizontal and one horizontal. Assuming no air resistance, which brick has the highest speed by the time it reaches the ground?

My answer: Simple conservation of energy... mgh = 0.5mv^2. They all have the same velocity... is this correct? Just wanted to confirm

2) If 2 cars crash, which would you expect to be more harmful to the passengers: if the cars crash and stay together, or if the cars collide and rebound backward? Explain.

My answer: Honestly, I am not sure at all. Momentum is conserved in both, thus impulse is 0. Only thing is... energy is lost in a sticky collision, so I'm going with an inelastic collision. However, I cannot explain it.



3) Can the total mechanical energy be negative? E = KE + PE
Explain + provide an example.

My answer: I always learned that energy is positive. But I'm thinking this can depend on the point of reference. If my reference point is 1000m above a cliff, the potential energy of a rock on the cliff is negative and has no kinetic energy... so E is -ive.
 
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For 2) what's harmful to the passengers is the acceleration. Assuming both collisions happen in the same time t at the same velocity v, then in one case they decelerate from v to 0 in time t. In the other they decelerate from v to 0 and then up to the rebound velocity in the same time. In which case is the magnitude of the acceleration larger? 1) looks fine. And yes for 3). KE is positive but PE depends on a choice of origin and can certainly be negative.
 
Dick said:
For 2) what's harmful to the passengers is the acceleration. Assuming both collisions happen in the same time t at the same velocity v, then in one case they decelerate from v to 0 in time t. In the other they decelerate from v to 0 and then up to the rebound velocity in the same time. In which case is the magnitude of the acceleration larger? 1) looks fine. And yes for 3). KE is positive but PE depends on a choice of origin and can certainly be negative.

So in fact, the total mechanical energy can be negative then... it all depends on the magnitude of the values?
 
lollol said:
So in fact, the total mechanical energy can be negative then... it all depends on the magnitude of the values?

Sure. PE can be negative, so if it's magnitude is greater than KE, the total is negative.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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