Which Cart Sinks Less in Rainy Weather: Wide or Thin Wheels?

  • Thread starter Thread starter andyboy179
  • Start date Start date
  • Tags Tags
    Wheels
AI Thread Summary
In rainy weather, a cart with wide wheels sinks less into soft ground compared to one with narrow wheels due to the distribution of weight over a larger surface area. This distribution reduces the pressure exerted on the ground, preventing the wheels from sinking as much. The concept of pressure is key to understanding this phenomenon. Wider wheels effectively spread the cart's weight, making them more suitable for soft, muddy conditions. Therefore, wide wheels are advantageous for maintaining stability in wet environments.
andyboy179
Messages
13
Reaction score
0
hi, this is my question:

A farmer has two carts. The carts have the same weight, but one has four narrow wheels and the other has four wide wheels. In rainy weather, which cart sinks less into soft ground, and why?

would it be the wide wheels because the weight is spread?
 
Physics news on Phys.org
Hi andyboy179, welcome to PF. That answer sounds good to me. What do we call the distribution of weight over area?
 
Mapes said:
Hi andyboy179, welcome to PF. That answer sounds good to me. What do we call the distribution of weight over area?

thanks for answering, is it pressure?
 
Bingo!
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

How Does Weight Distribution Affect the Balance of a Ferris Wheel?
Replies
3
Views
2K
Impulse and Momentum: Ball and cart connected by a cord
Replies
24
Views
3K
Newton's 3rd law: motorized cart pushes a heavy cart
Replies
25
Views
3K
How Much Energy Is Needed to Move and Rotate a Weighted Tray Using Rubber Tires?
Replies
3
Views
1K
Wheel ground pressure vs wheel size
Replies
35
Views
9K
Conservation of energy question.
Replies
4
Views
1K
B Roulette wheel physics and probability
Replies
9
Views
5K
I How Does Changing Mass and Spring Force Affect Watch Oscillators?
Replies
11
Views
2K
How fast will two spinning weighted wheels propel a 7 lb cylinder?
Replies
19
Views
3K
Calculating weights on a slope using virtual work.
Replies
15
Views
2K

Hot Threads

Recent Insights

Back
Top