Which expansion is used for this result?

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The discussion focuses on the approximation of the expression exp(hv/kT) - 1 when hv is much less than kT, which simplifies to hv/kT. Participants recognize this result as part of the Maclaurin series expansion for the exponential function. The conversation highlights the importance of understanding various expansions, particularly in the context of physics and thermodynamics. A link to a resource on Maclaurin series is shared for further reference. Overall, the thread emphasizes the relevance of mathematical expansions in scientific applications.
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exp (hv/kT) - 1



For hv<<kT



exp (hv/kT) - 1 is approximately equal to hv/kT


thanks for any ideas.
 
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How many expansions do you know?

exp(x) ~ 1+x should look familiar.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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