Which Legs Experience Total Internal Reflection in a 45,45,90 Glass Prism?

AI Thread Summary
In a 45,45,90 glass prism with a refractive index of 1.52, light entering at a right angle to one leg will transmit to the hypotenuse but may reflect at the other legs. The discussion revolves around understanding how light behaves at the hypotenuse and the subsequent legs when it exits into air. When light strikes the hypotenuse, it can undergo total internal reflection if the angle of incidence exceeds the critical angle. The critical angle can be calculated using Snell's law, which helps determine the behavior of light at the prism's boundaries. Ultimately, the light ray's behavior at the legs depends on the angles of incidence and the refractive indices involved.
kthejohnster
Messages
23
Reaction score
0

Homework Statement


A 45,45,90 glass triangular prism (n=1.52) is surrounded by air. If a light ray comes into one of the legs (not hypotenuse) at a right angle which legs have total internal reflection?

Homework Equations



n_1sinx_i=n_2sinx_r

The Attempt at a Solution


i figured out that the light ray on the first incident leg transmits light to hypotenuse at but am getting confused on how to get the reflection angle at the hypotenuse to figure out how light hits the other leg

Edit: the light comes in at the arrow at a right angle. What happens to light at side b and c in the attached pic
 

Attachments

  • Screen Shot 2012-03-13 at 11.13.42 PM.png
    Screen Shot 2012-03-13 at 11.13.42 PM.png
    3.1 KB · Views: 547
Last edited:
Physics news on Phys.org
The angle of incidence i = 0o since the ray comes at right angle.
 
What happens to light at side b and c
Consider the ray striking side c and emerging into air. Because air is a less dense medium, that ray as it emerges into air is angled further away from the normal than was the incident ray. Just how much further? https://www.physicsforums.com/images/icons/icon2.gif Apply that formula you provided.
 
Last edited by a moderator:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top