Which Liquid Would Form the Densest Vapor Upon Heating?

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The discussion revolves around determining which liquid produces the densest vapor upon heating, with the consensus identifying option C (CH3(CH2)4CH2Br) as the correct answer. The reasoning highlights that at standard conditions, the molar volume of the liquids is similar, impacting vapor density. There is confusion regarding the relationship between intermolecular forces, vapor pressure, and molar mass, with a comparison to gases like hydrogen and sulfur hexafluoride for context. The conversation emphasizes the importance of considering these factors when evaluating vapor density in future problems. Understanding the interplay of molecular weight and intermolecular forces is crucial for accurate assessments in chemistry.
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Homework Statement


Which of the following liquids would form the densest vapor upon heating?
A. CH3CH2CH2OH
B .CH3(CH2)3CH2Cl
C. CH3(CH2)4CH2Br
D. (CH3)3CCH2OH

Homework Equations


None really

The Attempt at a Solution


Now I know the answer already, its C. My question is why? I got B, my reasoning was that it is the lightest and has the least inter-molecular forces, which would result in a higher vapor pressure at a given temperature. Now the solution states it is C because at standard conditions, the molar volume is roughly the same. Does this mean, at the same temperature and pressure, the vapor pressure above each solution will be roughly the same?
 
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Which gas is more dense: hydrogen, or sulfur hexafluoride?
 
That would be sulfur hexafluoride. But my confusion is that in the question, the molecules are liquids and are producing vapor while still in the liquid phase. So is the question that I posted asking about which vapor is densest when both are produced to equal volume? Don't they have different imf and M.W. so that each liquid produces different amounts of vapor pressure at a given temperature?
 
Different pressures of the saturated vapor for sure, but I don't think you have enough information to judge that (especially when there are opposite effects at work). Approach based just on the molar mass is easy to defend - you compare things assuming everything else is identical.
 
Ah I see, that'll be important to consider in future questions. Thanks!
 
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