Which notation for pion(0) makeup is correct?

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The discussion centers on the correct notation for the pion(0) makeup, with a focus on the expression involving quark-antiquark pairs. One source presents the pion as a combination of up and down quarks with a specific sign configuration, while others suggest variations, particularly regarding the presence of a minus sign. It is noted that the sign may not significantly impact calculations if consistency is maintained throughout. The importance of the sign is highlighted in relation to G parity, and there is a consensus that the minus sign is more commonly used. Ultimately, clarity and consistency in notation are emphasized as crucial for accurate representation in quantum mechanics.
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In my book (Greiner's Quantum Mechanics, vol2, symmetries) says after calculation with Clebsch-Gordan coefficients,

|\pi^0\rangle = \frac 1 2 (u\uparrow \overline{u} \downarrow + d\uparrow \overline{d} \downarrow - u\downarrow \overline{u} \uparrow - d\downarrow \overline{d} \uparrow ),

And I confirmed it.

Ignoring spin, It's |\pi^0\rangle = \frac 1 {\sqrt{2}} (u \overline{u} + d \overline{d})

However, some sites denote, it's the same: the sum (ex, this one, but others denote it's different; minus sign (ex. this one).

I wonder which is correct. I konw Internet resource is sometimes incorrect. And the latter is wiki... Or they mean the same? because u \overline{u} and d \overline{d} are orthogonal.

But if I do \hat{T_-}|\pi^+}\rangle = \hat{T_-}u\overline{d} = \frac 1 {\sqrt{2}} (u\overline{u} + d\overline{d}), only plus is correct. (phase is ignored and each hand is normalized.)

So will anyone give me any hint which is correct or both are correct? I think at least plus is correct.

Thanks in advance!
 
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That sign is different in different books.
Many times the sign doesn't matter in a particular calculation if yhou are consistent throughout.
I think the minus sign is more common.
That is related to the common usage that charge conservation turns the d into -dbar (if I remember it correctly).
The Ispin doublet for the antiquarks is (ubar,-dbar).
Just be consistent in whatever you do.
I think the sign is only important in getting the G parity right.
 
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Meir Achuz said:
That sign is different in different books.
Many times the sign doesn't matter in a particular calculation if yhou are consistent throughout.
I think the minus sign is more common.
That is related to the common usage that charge conservation turns the d into -dbar (if I remember it correctly).
The Ispin doublet for the antiquarks is (ubar,-dbar).
Just be consistent in whatever you do.
I think the sign is only important in getting the G parity right.

Thank you for the reply. I don't understand exactly what you mean right now (why ispin doublet for the antiquarks is (\overline u,-\overline d). In my understanding, it's (\overline u, \overline d) and it must make difference), but I'll proceed keeping it in mind, because I don't have a book denoting minus explicitly...

Thanks.
 
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