Which Phase Can Withstand a Force?

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The discussion centers on which phase of matter can permanently withstand a perpendicular force, with the consensus that all phases—gas, liquid, and solid—can do so under certain conditions. While gases are more compressible than liquids and solids, they still transmit forces to their containers when compressed. The concept of "withstanding a force" involves the ability of molecules to transmit force through compression, regardless of the phase. It is noted that in practical applications, gases, liquids, and solids are often treated as incompressible for simplification in calculations. Ultimately, all matter must be able to withstand forces to maintain structural integrity.
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Homework Statement



Which of the following phases is capable of permanently withstanding a force perpendicular to its surface?

A. Gas
B. Liquid
C. Solid
D. All of the above

Homework Equations





The Attempt at a Solution



I understand that the answer is D.
However, what does it mean to withstand a force? if a gas is in a cylinder with a moveable piston, and then a mass is placed on the piston, the gas would be compressed. So I'm not sure what an example of a gas withstanding a perpendicular force would be.

Thanks in advance!
 
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Actually, technically all matter is and must be "compressed" in order to withstand a force. The molecules in a substance (whatever physical state it is in) need to transmit the force down to it's container or supports. This is achieved by squeezing the molecules closer together since the repulsive force between atoms increases as they get closer together.

A gas is just more compressible than a liquid which in turn is more compressible than a solid. Sometimes to simplify the mathematics we assume a gas or liquid or solid is "incompressible" which simply means that the change in volume is small enough that we can safely neglect it without losing accuracy.
 
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Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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