Which Quantum Numbers Are Not Possible for Arsenic?

AI Thread Summary
The discussion centers on identifying which set of quantum numbers cannot describe an electron in an arsenic atom in its ground state. The correct answer is that the set (4, 2, 2, -1/2) is not possible because arsenic does not have electrons in the 4d orbital in its ground state. Participants clarify that while all quantum numbers are theoretically valid, the specific electron configuration of arsenic dictates the limitations. The ground state electron configuration for arsenic is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3, confirming that 4d orbitals are unoccupied. Understanding the relationship between quantum numbers and electron configuration is crucial for determining valid sets for specific elements.
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11. Which one of the following sets of quantum numbers (n, l, ml, ms) could not possibly describe one electron of an arsenic atom (Z = 33) in its ground state?

(A) 2, 1, -1, 1/2
(B) 4, 2, 2, -1/2
(C) 3, 0, 0, -1/2
(D) 3, 2, -2, 1/2
(E) 4, 1, 0, 1/2

Solution:

Electron configuration for arsenic:
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3

2, 1, -1, 1/2 represents a 2 p electron, possible.
4, 2, 2, -1/2 represents a 4 d electron, NOT possible for As.
3, 0, 0, -1/2 represents a 3 s electron, possible.
3, 2, -2, 1/2 represents a 3 d electron, possible.
4, 1, 0, 1/2 represents a 4 p electron, possible.

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I don't understand why its the second one, I do know that all of the numbers are allowed for n, l, ml, ms, but i don't understand how it changes when the element As comes into play.

Thanks for any help
 
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Does As have electrons on 4d when in ground state?
 


Oh ok, that's what i didn't understand in quantum numbers, l of 2 indicates a d orbital, but as has no electrons in a d orbital in ground state. thx
 


lost_in_phys said:
l of 2 indicates a d orbital, but as has no electrons in a d orbital in ground state. thx

Yes it has - but on 3d, not 4d.
 


Sorry, yea, that's what i meant, thx
 
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