Which reactant is the limiting reagent?

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To determine the limiting reagent in the reaction 2C2H4 + Br2 + Cl2 → 2C2H4ClBr, the mole ratios of the reactants must be analyzed. Given 15 L of C2H4, 20 L of Br2, and 10 L of Cl2 at STP, the moles of each gas can be calculated using the ideal gas law, where 22.4 L corresponds to 1 mole. The calculated moles show that 20 L of Br2 corresponds to approximately 0.892 moles, which requires at least 0.892 moles of Cl2 and 1.784 moles of C2H4 to fully react. Comparing the available moles reveals that one of the reactants will be limiting if there is an insufficient amount of it relative to the others. Identifying the limiting reagent is crucial for understanding the yield of the reaction.
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My sister tried many ways to get this solution but it didnt work so she needs your help on how to do this problem. Plz Plz Plz do it before 10:00 PM.


2C2H4 (g) + Br2 (g) + Cl2 (g) -----) 2C2H4ClBr(g)

A Skyline student reacts 15 L of C2H4, 20 L of Br2 (g) and 10 L of Cl2 to form C2H4ClBr(g). Assume the gasses begin the reaction at STP.

Which reactant is the limiting reagent?
 
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From the balanced chemical reaction , you know the mole ratios of all the products to each other (2 moles C2H4 : 1 mole Br2 : 1 mole Cl2).

Since you know the volumes of each gas used in the reaction and their temperature and pressure (STP), you can find the mole ratios present at the start of the reaction. At STP, an ideal gas has a volume of 22.4 Liters, so from this, we can calculate the number of moles of each gas. After knowing the number of moles actually present, compare it to how many moles should be there of the other gasses, minimum, assuming that the gas in question is not the limiting reactant.

For example,
20 Liters of Br2 is about .892 moles of Br2, so in theory, there should be at least .892 moles of Cl2 and 1.784 moles of C2H4. Are there? If there is too much of the other reactants, it is possible that the gas in question is the limiting reactant.
 
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