Solving the Mystery: Which Tank Fills First?

[fahraynk]

I originally thought tank K because the area in tank J is much larger than the area in the pipe connecting J to I
But then I realize Bernoulli's equation does not include volume but only includes height.
H_1, H_2 = height of water tank J, height of water in pipe between tanks J and I
P, p, V = pressure, density, velocity
$$P_1+pgH_1+\frac{1}{2}pV_1^2=P_2+pgH_2+\frac{1}{2}pV_2^2$$
Pressure terms are the same, so is density. Velocity = 0, gravity cancels out $H_1=H_2$
So even in the small pipe connecting J to I, the water level is going to be the same as the height of water in the tank J.

Is this correct?

Also note the pipe from C to D is blocked off.
Also I assume A would be trivial solution so water must exit pipe faster than the tap fills tank A

 

[jbriggs444]

The water is dripping in. Flow velocity will be negligible.

 

[Regla]

It really depends on what point do you consider the tank is 'full', let's say that the point full is when the tank is overfilling. I think the tank H would get filled first because the connection JI goes higher than connection JL.

 

[jerromyjon]

I say F will fill up (overflowing) first!

 

[jbriggs444]

It really depends on what point do you consider the tank is 'full', let's say that the point full is when the tank is overfilling. I think the tank H would get filled first because the connection JI goes higher than connection JL.

There is no path into tank H.

 

[Regla]

There is no path into tank H.

whoops that's true. Then my guess is F. Thanks.

 

[CWatters]

Tank G fills up first. The water flows A B C D G. No water goes into J. No water goes into E.

Darn I didn't spot the blocked pipe. Ok so yes it's F.

 

[phinds]

It's G

 

[Nugatory]

It's G

You've missed the blocked pipe C to D.

 

[Nugatory]

A and B fill to the level of their outputs; C fills to the level of its outlet into J; J fills to the level of its outlet into L; L fills to the level of the top of F; and F fills and overflows. Once F is full, every drop of water into A causes another drop to overflow from F and the system is in steady state.

 

[phinds]

You've missed the blocked pipe C to D.

Damn ! Thanks.

CWaters even SAID it was there and I still couldn't see it.

 

[fahraynk]

A and B fill to the level of their outputs; C fills to the level of its outlet into J; J fills to the level of its outlet into L; L fills to the level of the top of F; and F fills and overflows. Once F is full, every drop of water into A causes another drop to overflow from F and the system is in steady state.

So, basically, the area doesn't matter of tank J, it won't push the water through the pipe higher than its own water level? Tank J is roughly 27 times the cross sectional area then the pipe... but it doesn't matter right?

 

[Nugatory]

So, basically, the area doesn't matter of tank J, it won't push the water through the pipe higher than its own water level? Tank J is roughly 27 times the cross sectional area then the pipe... but it doesn't matter right?

Not as long as the rate at which water enters the tank is small compared with the rate at which a single pipe can carry the water out - the water level will not rise above the height of the lowest flowing pipe. The illustration suggests that we're dealing with a dripping faucet which will easily be handled by a single pipe - think about an air conditioning unit's condensate drain tray.

 

[Gurjeet210]

It's K

 

[Nugatory]

It's K

Can't be - nothing flows from J to I because the level in J doesn't rise above the outlet from J to L.

 

[Stressil]

I choose L due to pressure and flow

 

[RonL]

I say F will fill up (overflowing) first!

I agree with you, F will overflow before any others

 

[davenn]

I choose L due to pressure and flow

no ... look again ... F is at a lower level than L which fills F

Like phinds and a couple of others, I originally was going for G as I didn't see the block between C and D

 

[DrGreg]

Here's the picture for the slow-drip steady-state solution:

Spoiler

 

[Dr_Zinj]

View attachment 208203

I originally thought tank K because the area in tank J is much larger than the area in the pipe connecting J to I
But then I realize Bernoulli's equation does not include volume but only includes height.
H_1, H_2 = height of water tank J, height of water in pipe between tanks J and I
P, p, V = pressure, density, velocity
$$P_1+pgH_1+\frac{1}{2}pV_1^2=P_2+pgH_2+\frac{1}{2}pV_2^2$$
Pressure terms are the same, so is density. Velocity = 0, gravity cancels out $H_1=H_2$
So even in the small pipe connecting J to I, the water level is going to be the same as the height of water in the tank J.

Is this correct?

Also note the pipe from C to D is blocked off.
Also I assume A would be trivial solution so water must exit pipe faster than the tap fills tank A

Tank F will fill up first

 

[The Wizard]

Flow Chart is A - B - C - J - L - F

No tank will fill before F and as F is open at the top it will constantly overflow, therefore no other Tank can fill fully.

 

[Ron G]

F fills first; L prevents any flow reaching I from J because inlet to I is higher than outlet to L. J must fill before any tank above (A, B, or C).
BUT ASSUMPTIONS ARE EVERYTHING.
F fills first only if 1) all the pipes are the same diameter and of the same material, 2) the heights of all tanks are identical, 3) the flow from the faucet does not exceed the pipe capacity (as indicated by the drip), and 4) therefore, flow through system is not sufficient to impact dynamic pressure caused by line friction and elbows. With these assumptions, the only law needed is water seeking lowest level.

Once you violate any of these assumptions, you will need to work through the system performance using the Bernoulli's equation; and the complexity of the system increases substantially, probably requiring a full dynamic modeling exercise.

EXAMPLE: Let's just change one assumption: that the faucet inflow exceeds the outflow capacity of Tank A, even when tank A is full.
When the faucet flow rate exceeds the outflow pipe capacity, A will begin to fill to over flowing. As it does, the pressure at the outlet will increase, thereby increasing the outflow rate. Thus, the inflow to i B will be greater than the outflow from B to C, and B will begin to fill. Since the outlet from B is lower relative to the tank height than is the outlet from tank A, at some point, the outflow from B may match that from A. The height difference of the two tanks as well as the depth of the outlet of the tank will determine whether B will over flow. It does appear that tank B is taller than tank A and that the A outlet is not as deep at the B outlet, thus the level in B will stabilize below over flow. This same exercise must now proceed through each box.Reference https://www.physicsforums.com/threads/which-tank-fills-first.921715/

 

[Matt Chipman]

No liquid will ever reach D, E or G...due to the closed off pipe from C to D...so none of them

 

[Mike Bergen]

View attachment 208203

I originally thought tank K because the area in tank J is much larger than the area in the pipe connecting J to I
But then I realize Bernoulli's equation does not include volume but only includes height.
H_1, H_2 = height of water tank J, height of water in pipe between tanks J and I
P, p, V = pressure, density, velocity
$$P_1+pgH_1+\frac{1}{2}pV_1^2=P_2+pgH_2+\frac{1}{2}pV_2^2$$
Pressure terms are the same, so is density. Velocity = 0, gravity cancels out $H_1=H_2$
So even in the small pipe connecting J to I, the water level is going to be the same as the height of water in the tank J.

Is this correct?

Also note the pipe from C to D is blocked off.
Also I assume A would be trivial solution so water must exit pipe faster than the tap fills tank A

Through observation, looks like G would fill first' others will just move the water to other places
IMHO

 

[jbriggs444]

Through observation, looks like G would fill first' others will just move the water to other places
IMHO

If you review the original post in this thread you will see why that is not correct. Several others have already missed seeing:

Also note the pipe from C to D is blocked off.

 

[RonL]

F fills first; L prevents any flow reaching I from J because inlet to I is higher than outlet to L. J must fill before any tank above (A, B, or C).
BUT ASSUMPTIONS ARE EVERYTHING.
F fills first only if 1) all the pipes are the same diameter and of the same material, 2) the heights of all tanks are identical, 3) the flow from the faucet does not exceed the pipe capacity (as indicated by the drip), and 4) therefore, flow through system is not sufficient to impact dynamic pressure caused by line friction and elbows. With these assumptions, the only law needed is water seeking lowest level.

Once you violate any of these assumptions, you will need to work through the system performance using the Bernoulli's equation; and the complexity of the system increases substantially, probably requiring a full dynamic modeling exercise.

EXAMPLE: Let's just change one assumption: that the faucet inflow exceeds the outflow capacity of Tank A, even when tank A is full.
When the faucet flow rate exceeds the outflow pipe capacity, A will begin to fill to over flowing. As it does, the pressure at the outlet will increase, thereby increasing the outflow rate. Thus, the inflow to i B will be greater than the outflow from B to C, and B will begin to fill. Since the outlet from B is lower relative to the tank height than is the outlet from tank A, at some point, the outflow from B may match that from A. The height difference of the two tanks as well as the depth of the outlet of the tank will determine whether B will over flow. It does appear that tank B is taller than tank A and that the A outlet is not as deep at the B outlet, thus the level in B will stabilize below over flow. This same exercise must now proceed through each box.Reference https://www.physicsforums.com/threads/which-tank-fills-first.921715/

It seems like you are trying to set the question of what flow from the faucet, with the assist from gravity, will all tanks reach the full mark before anyone of them overflows. I think (gut feeling) there might be an answer, though the math is far over my head.

 

[calinvass]

When the water level exceeds the height of the end of the pipe the water will flow through it. For this rule the tanks need to have no lid You only need to be careful a about details. (The answer is clearly F).
For example if you let the water go between C and D and block the pipe between D and G, after the water level nearly reaches the top of D it will start to run through the pipe and fill E as well. Then D and E will fill up to the top at the same time.
Placing a lid on C makes no difference on the result but placing a lid on F might prevent filling it up and the air pressure inside will go up.

 

[Skeptic Tom]

It is tank F, if it's not, I will eat my hat !

 

[davenn]

No liquid will ever reach D, E or G...due to the closed off pipe from C to D...so none of them

this is incorrect ... obviously you haven't read the earlier posts

It is tank F, if it's not, I will eat my hat !

you need to read the earlier posts as well

the answer "F" has been well established

 

[Number 42]

Obviously it is H
Just follow the lowest outlet of the tanks and end up in H
Assuming All pipes are about same dimensions.

Pipe to G is closed, assuming it is not a drawing error