Who can fill the brace: -3,0,26,252,()

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The discussion revolves around a mathematical sequence represented by the brace -3,0,26,252,() and the potential integers that could fill the empty slot. Participants speculate on the conditions and patterns that govern the sequence, with suggestions that it may relate to an IQ test involving number patterns. One user proposes changing the first number to -6, leading to a sequence derived from powers of 2, resulting in different interpretations based on the sequence type. The conversation highlights the ambiguity in determining the next number, depending on whether the sequence follows Fibonacci or quadratic rules. Ultimately, the thread emphasizes the complexity and variability of mathematical sequences.
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who can fill the brace:
-3,0,26,252,()
thanks a lot!
 
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?? In what way? is there any reason that brace could not contain any integer? What are the conditions you are not telling us about?
 
most probably it's some pointless IQ test where we go on filling in patterns and numbers and all that stuff..
 
Whew. I get
\sigma(4n\cdot2^{2^{2^{3-1}}})-4=2,097,144
There's no rounding needed since it's even.
 
CRGreathouse said:
Whew. I get
\sigma(4n\cdot2^{2^{2^{3-1}}})-4=2,097,144
There's no rounding needed since it's even.

d00d seriously.. what did u just do??
 
CRGreathouse said:
Whew. I get
\sigma(4n\cdot2^{2^{2^{3-1}}})-4=2,097,144
There's no rounding needed since it's even.

Oh, well, of course!
 
Can you change the first to -6, instead of -3?
 
in any way i think.there are many answers if you can tell the reason.
to Dodo, if u change the first to -6,what is your answer?thank u!
 
With a -6... is it ambiguous. It would be the sequence
2^2-10, \ \ \ \ \ \ 2^3-8, \ \ \ \ \ \ 2^5-6, \ \ \ \ \ \ 2^8-4​
so the next is 2^n-2, and n depends on how you interpret the sequence of exponents: if it is Fibonacci, then n=11 for a value of 2046, if it is a quadratic, n=12 and you get 4094.
 

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