Who is correct and why?Is the Momentum Conserved in this Collision?

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The discussion revolves around a physics problem involving a collision between two particles of different masses. After the collision, the lighter particle (mass m) comes to rest, while the heavier particle (mass 2m) splits into two particles, each having both x and y components of velocity, separated by an angle θ. There is a debate among commenters regarding the conservation of momentum in the x direction. One commenter asserts that the x component of velocity for each resulting particle is v/2, based on the principle of horizontal momentum conservation. Another commenter challenges this, suggesting that the x components could vary, such as v/3 and 2v/3, unless the split is symmetric. The discussion highlights the need for clarity on the angle θ and the direction of motion, as the interpretation of the x-axis is crucial to understanding the velocity components post-collision.
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http://grephysics.net/ans/0177/55

The question hasn't been typed up yet but it's pretty basic. A particle of mass m runs into a particle of mass 2m. After the collision, the particle with m is at rest and the particle of mass 2m has split into two particles each with mass that have both y and x components to their velocity, separated by θ.

If you look at the people that commented on this question there seems to be a bit of debate. One quite intelligent and confident poster wrote that the velocity in the x direction for each particle is equal to v/2, since the initial velocity was v and horizontal momentum must be conserved. Another poster wrote that the x component of velocity for each particle does NOT equal v/2 because they aren't moving along the x-axis.

Who is correct and why?

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PsychonautQQ said:
The question hasn't been typed up yet but it's pretty basic. A particle of mass m runs into a particle of mass 2m. After the collision, the particle with m is at rest and the particle of mass 2m has split into two particles each with mass that have both y and x components to their velocity, separated by θ.
A full statement of the problem would help. The angle θ is the angle between the two split particles or is the angle they both make with the original direction of the first particle (as one comment assumed)?

If you look at the people that commented on this question there seems to be a bit of debate. One quite intelligent and confident poster wrote that the velocity in the x direction for each particle is equal to v/2, since the initial velocity was v and horizontal momentum must be conserved.
Why couldn't the x-components be v/3 and 2v/3? Unless the split is symmetric.

Another poster wrote that the x component of velocity for each particle does NOT equal v/2 because they aren't moving along the x-axis.
I don't know what that is supposed to mean. I assume that the x-axis is the direction of motion of the first particle.
 
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