Why 2p=ln[(1-cost)/(1+cost)] => t=(1/coshp)^2

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The discussion centers on the mathematical equation 2p=ln[(1-cost)/(1+cost)] and its implication t=(1/coshp)^2. Participants express confusion over the correctness of the equation, suggesting an alternative form involving sin²t. There is a call for clarification on the specific question being posed, emphasizing the need for the original poster to demonstrate their understanding or effort in solving the problem. Overall, the conversation highlights the importance of clear communication and foundational knowledge in mathematical discussions.
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why
2p=ln[(1-cost)/(1+cost)] => t=(1/coshp)^2

?
?
 
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why not?
 
i think you wrote it wrong. it should be
\sin^{2}t = \left(\frac{1}{\cosh p}\right)^2
 
astronomia84 said:
why
2p=ln[(1-cost)/(1+cost)] => t=(1/coshp)^2

?
?

What is the actual question you are asking here? Are you asking why, or if, the left implies the right. Have you done anything to attempt to show this? I doubt anyone will help unless you firstly specify your question, and secondly show some effort!
 

Thread 'Greatest possible value of a constant in polynomial'

Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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