Why a bulb glow dimmer in beginning and then brighter

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Discussion Overview

The discussion revolves around the behavior of a light bulb connected to an inductor, specifically why the bulb glows dimmer initially and then becomes brighter. The scope includes theoretical explanations and mathematical reasoning related to inductance and current behavior in circuits.

Discussion Character

  • Exploratory, Technical explanation, Homework-related, Mathematical reasoning

Main Points Raised

  • Some participants propose that the inductor prevents the current from switching instantaneously, causing the current to rise slowly to its final value.
  • One participant suggests that the rate at which the inductor allows current to rise is proportional to the voltage across it, leading to a differential equation that can be solved to find the current as a function of time.
  • A later reply questions the maximum value of voltage or current in the circuit.
  • Another participant states that the maximum value, which is the final steady-state value, will be equivalent to what would be obtained if the inductor were removed and replaced with a wire.

Areas of Agreement / Disagreement

Participants express differing views on the specifics of the current and voltage behavior, and while some explanations are presented, no consensus is reached regarding the maximum values or the implications of the inductor's behavior.

Contextual Notes

Limitations include the dependence on assumptions regarding the circuit configuration and the mathematical treatment of the inductor's properties, which are not fully resolved in the discussion.

amaresh92
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Homework Statement


greetings
why a bulb glow dimmer in beginning and then brighter when it is connected to a inductor?
 
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Because, inductor won't let current to switch instantaneously, i.e., it will make current rise slowly to its final value.
If you work out the math by assuming that the rate at which inductor let's current to rise is proportional to voltage across it, i.e. dI/dt = (1/L) V, then applying KVL, you will come to a differential equation.
Solving the differential equation, you will get expression for current, i.e. current as a function of time, I(t), which will give you all the information you need.
 


thecritic said:
Because, inductor won't let current to switch instantaneously, i.e., it will make current rise slowly to its final value.
If you work out the math by assuming that the rate at which inductor let's current to rise is proportional to voltage across it, i.e. dI/dt = (1/L) V, then applying KVL, you will come to a differential equation.
Solving the differential equation, you will get expression for current, i.e. current as a function of time, I(t), which will give you all the information you need.

what will be the maximum value of votage or current?
 


The maximum value which is the final steady state value will be equivalent to what will be obtained if you remove the inductor and join with wire.
 

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