Why Are 0 and 4 Excluded from the Range in This Function?

  • Thread starter Thread starter coconut62
  • Start date Start date
  • Tags Tags
    Function Range
AI Thread Summary
The discussion centers on the exclusion of 0 and 4 from the range of a function, with the initial answer suggesting the range should be 0 ≤ x ≤ 4. However, the correct range is stated as 0 < x < 4, prompting questions about the reasoning behind this exclusion. One participant argues that since the domain includes 6, which leads to a calculation of 4, both endpoints should be included. Ultimately, it is clarified that 0 and 4 are indeed part of the range, despite the initial confusion. This highlights the importance of understanding the definitions of open and closed intervals in mathematical functions.
coconut62
Messages
161
Reaction score
1

Homework Statement


Please refer to the image attached. The first part, (i).

Homework Equations


None.

The Attempt at a Solution



My answer is 0 </= x </= 4, but the answer says 0<x<4.
Why are 0 and 4 not included?

Since the domain includes 6, then 0.5(6)+1 =4, 4 should be included right?
 

Attachments

  • 1382416_10151787991817830_1912930532_n.jpg
    1382416_10151787991817830_1912930532_n.jpg
    27.7 KB · Views: 514
Physics news on Phys.org
coconut62 said:

Homework Statement


Please refer to the image attached. The first part, (i).

Homework Equations


None.


The Attempt at a Solution



My answer is 0 </= x </= 4, but the answer says 0<x<4.
Why are 0 and 4 not included?

Since the domain includes 6, then 0.5(6)+1 =4, 4 should be included right?

You are right,0 and 4 are part of the range.
 
  • Like
Likes 1 person
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top