Why are the charges on capacitors A and B the same, and C and D equivalent?

AI Thread Summary
Capacitors A and B, as well as C and D, are connected in series, which means they share the same charge due to the nature of current flow in series circuits. When a current enters capacitor A, it must also flow into capacitor B, resulting in equal charge on both. Similarly, capacitors C and D experience the same charge because the current flowing through them is also identical. The charge redistribution occurs without any external charge entering the system; it is merely a result of the battery's influence on the connected plates. Thus, regardless of the number of capacitors in series, each will maintain the same charge as dictated by the battery's operation.
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http://capa.physics.mcmaster.ca/figures/sb/Graph26/sb-pic2654.png
This is more of a concept understanding if anything but I'm interested to know why the charge on capacitors A and B are the same and similarly, the charge on capacitor C and D are equivalent.
 
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maiad said:
http://capa.physics.mcmaster.ca/figures/sb/Graph26/sb-pic2654.png
This is more of a concept understanding if anything but I'm interested to know why the charge on capacitors A and B are the same and similarly, the charge on capacitor C and D are equivalent.

Capacitors A and B are connected in series, as are capacitors C and D. Components in series always carry the same current -- so any charge that moves into or out of capacitor A must also move into or out of capacitor B. Similarly with capacitors C and D.
 
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Yes they are, unless it is a weird setup where one had a charge before they were connected. You can see the reason easily. The wire between Ca and Cb was originally neutral. When a current flows into that branch, it cannot flow through a capacitor because of the gap between the plates. So it just separates the charge on the wire between so a +q appears on one capacitor and a -q on the other, keeping the whole wire neutral as it must be.
 
Yours seem more reasonable so does that mean gneill's response is incorrect? You explanation would also explain why The charge in A and B is simpliy Q=C(eq)ΔV
 
Both explanations are correct. They are just different ways conceptually of looking at the situation.
 
Another good way to look at it is from the point of view of the battery. The + of the battery is connected to the plate on the left (of Cc) and the - of the battery is connected to the plate on the right (of Cd). These are the only plates connected to the battery.
The battery transfers -charge from the left plate to the right plate. This is the only charge that flows round the external circuit, through the battery. The other + and - charges you see on the capacitors are just charges that have been re-distributed, they have not come from 'outside'.
It does not matter how many capacitors are in series. The charge on each one is the same and only one amount of charge has passed from the battery.
 
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