Why Can the Distance to the Second Source Vary in a Wave Interference Problem?

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In a wave interference problem involving two loudspeakers producing in-phase circular waves, the distance to the second source can vary due to the geometric arrangement of the speakers and the listener. The person on the sixth nodal line is fixed at 50m from one source, but the angle of observation allows for multiple distances to the second source. This variability arises from the nature of wave interference and the mathematical properties of trigonometric functions. The presence of multiple nodal lines means that there can be different configurations where the listener experiences constructive or destructive interference. Thus, the distance to the second source is not fixed and can change based on the listener's position relative to the speakers.
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Two loudspeakers are producing circular waves of 7m wavelength in phase. A person on the sixth nodal line is 50m from one source. What are the possible distances of the person from the other source?

I know how to do this question but I don't understand how there can be two different distances. The question states the person is 50m from one source and is on the sixth nodal line. So he shouldn't be able to move at all. If he is fixed 50m from one source, how can the distance to the other source vary? I even roughly drew it out but I can't see it. TiA

Preet
 
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The distance from the other speaker can vary depending in theangle at which the 50m difference is taken. As this is a trig function I would expect there to be limits as in theory there could be an infinite number of nodes (ignoring work done against resistive forces)
 

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