Why can't i apply the simple average velocity formula?

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Discussion Overview

The discussion revolves around the application of the average velocity formula, specifically the formula Vavg = (vf + vi) / 2, in the context of a non-linear position function x = 12t² - 2t³. Participants explore the conditions under which this formula is valid and the implications of using it for non-linear functions.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant notes an error in applying the average velocity formula Vavg = (vf + vi) / 2 for a non-linear position function.
  • Another participant explains that the formula is only valid for linear functions of time, indicating that the position function provided is non-linear.
  • A different participant confirms that the average velocity formula requires the function to be linear, suggesting that the correct approach involves integrating the function over the interval.
  • There is a clarification that the average velocity formula Vavg = (vf + vi) / 2 is contingent on the velocity being a linear function of time.
  • One participant expresses understanding of the condition attached to the simpler average velocity formula after receiving clarification.

Areas of Agreement / Disagreement

Participants generally agree that the average velocity formula Vavg = (vf + vi) / 2 is not applicable to non-linear functions, but the discussion remains unresolved regarding the implications of this for the specific homework problem.

Contextual Notes

The discussion highlights the importance of recognizing the type of function when applying average velocity formulas. There are unresolved aspects regarding the integration method suggested for non-linear functions and how it relates to the specific problem at hand.

rainstom07
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I'm doing a homework problem (i already know the answer) and i came across an error in my logic/application of the formula Vavg = (v + v0)/2. Hopefully you can help me understand why it's incorrect to use the formula.

x = 12t2-2t3 describes a particle position. the derivative of x = 24t-6t2.

The homework question asked me find the average velocity between t = 0 and t = 3.

Using the formula Vavg = Δx/Δt yields 18 m/s... the correct answer.

---
When i use the simpler formula: Vavg = (vf + vi) / 2 = (x'(3.0)+x'(0.0))/2 = 18/2. I get 9 m/s which is incorrect.

--
Adding the velocity at t=3 with the velocity at t=0 and then dividing by 2 should've produced 18 m/s... My logic is clearly wrong, but how?

x' describes the velocity of the particle at t seconds? right?

thanks.
 
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Hello rainstom, welcome to Physics Forums

Your average formula (t0+t3)/2 is only correct if x is a linear function of t ie a straight line.

The function x = 12t2-2t3 is decidedly non linear

The way to derive an average for a non linear function (works for linear as well but is trivial) is to integrate the function and divide by the interval or number of points or samples.

So average = Area/Interval

Does this help and can you now obtain the correct answer?
 
Your average formula (t0+t3)/2 is only correct if x is a linear function of t ie a straight line.

Thank you! i knew there was some sort of condition attached to the simpler version of average velocity.

Does this help and can you now obtain the correct answer?
^^ yup
 
Studiot said:
Hello rainstom, welcome to Physics Forums

Your average formula (t0+t3)/2 is only correct if x is a linear function of t ie a straight line.

The function x = 12t2-2t3 is decidedly non linear

I suppose you meant v_avg = (v_0 + v_3)/2 is only correct if v is a linear function of t.?

X must then be a quadratic function of t, and x = 12t2-2t3 isn't a quadratic.
 
Hello willem2 does this attachment help?

The average velocity is the number which if you multiplied it by the time would give you the total distance travelled.
 

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